I’m pretty sure the answer would be Y=42°
Answer:
measure it bro lol
Step-by-step explanation:
Answer:
A. 0.009899
B. 0.005624
Step-by-step explanation:
Data:
Let the probability that an item is defective = 
The probability that the item is not defective = 
The probability that the fifth item is defective = 
= 0.009899
Probability that one in 5 items is defective = 0.005624
A) 
B)In 200 times he can hit 59 times !
<u>Step-by-step explanation:</u>
Here we have , A baseball player got a hit 19 times in his last 64 times at bat. We need to find the following :
a. What is the experimental probability that the player gets a hit in an at bat?
According to question ,
Favorable outcomes = 19
Total outcomes = 64
Probability = (Favorable outcomes)/(Total outcomes) i.e.
⇒ 
⇒ 
b. If the player comes up to bat 200 times in a season, about how many hits is he likely to get?
According to question , In 64 times he hit 19 times . In 1 time there's probability to hit 0.297 times! So ,In 200 times he can hit :
⇒ 
⇒ Hit = 59.36
Therefore , In 200 times he can hit 59 times !
No it is not because its more then ten numbers away from the solution of the five tickets