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Fantom [35]
3 years ago
6

Practice solving for the volume of right and oblique

Mathematics
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:

volume = area of rectangle × height

= (x × x ) × 1/2x

= x² × 1/2x

= 1/2x³

the answer is the first option

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Here is an inequality: 7x+6/2 < 3x +2
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x=1

Step-by-step explanation:

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Which of the following ordered pairs could represent the x-intercept of a function?
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The answer is (15,0) because the format is (x,y) so (15,0) means that it is on the x axis only ! 
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How do you work out the value of x?
denis23 [38]

Answer: 45

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The total degrees in a circle is 360.

The perpendicular angle that you see is 90 degrees, added to angles of x and 3x, you get the total degrees.

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Read 2 more answers
State whether the following coordinates on a Cartesian plane form an acute, obtuse or right triangle: a) (-1, 1), (7,-2) and (1,
LiRa [457]

Answer:

a) Acute triangle

b) Right triangle

Step-by-step explanation:

∵ A triangle having sides a, b and c is called,

Acute : If a² + b² > c² or a² + c² > b² or b² + c² > a²,

Obtuse : if a² + b² < c² or a² + c² < b² or b² + c² < a²

Right : a² + b² = c² or a² + c² = b² or b² + c² = a²,

a) Let A≡(-1, 1), B≡(7,-2) and C≡(1,-5),

By the distance formula,

AB=\sqrt{(7-(-1))^2+(-2-1)^2}=\sqrt{(7+1)^2+(-3)^2}=\sqrt{8^2+3^2}=\sqrt{64+9}=\sqrt{73}\text{ unit}

Similarly,

BC=\sqrt{45}\text{ unit}

CA=\sqrt{40}\text{ unit}

∵ The sum of any two sides is greater than third side,

So, ABC is a triangle,

Now,

AB^2 + BC^2 > CA^2

⇒ ABC is an acute triangle.

b) Let P≡(0,6), Q≡(1,2) and R≡(5,3),

By the distance formula,

PQ = √17 unit,

QR = √17 unit,

RP = √34 unit,

∵ The sum of any two sides of PQR is greater than third side,

⇒ PQR is a triangle ,

Also,

RP^2=PQ^2+QR^2

Hence, PQR is a right triangle.

3 0
3 years ago
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