Question

A ball rolling down a hill was displaced 19.6 m while uniformly accelerating from the rest. If the final velocity was 5.00m/s, what was rate of acceleration?

Answer 1

we are given

A ball rolling down a hill was displaced 19.6 m

so,

$h=19.6m$

the final velocity was 5.00m/s

so, $v=5m/s$

Since, a ball rolling down a hill was displaced

so, we get

$u=0m/s$

we can use kinematic equation formula

$v^2-u^2=2ah$

Here ,

v is final velocity

u is initial velocity

a is acceleration

h is height from which ball is dropped

now, we can plug our values

$5^2-0^2=2a(19.6)$

$2a\left(19.6\right)=5^2$

$2a\left(19.6\right)=25$

$a=0.63776m/s^2$................Answer