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3 years ago

Graphing linear inequalities -four folded method y<3/2x-5

Mathematics

1 answer:

Volgvan3 years ago

8 0

A pump empties the pool at the rate of 1000 gals every 4 hours how long does it take to pump our 20,000 gallons

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Solve 2(4x + 5) > 7x + 20.

choli [55]

2(4x+5)>7x+20 perform indicated multiplication on left side

8x+10>7x+20 subtract 7x from both sides

x+10>20 subtract 10 from both sides

x>10

or in interval notation, x=(10, +oo)

8 0

3 years ago

1 -12.166 + (-1.54)

castortr0y [4]

Answer:

-12.706

Step-by-step explanation:

First we distribute: 1 - 12.166 - 1.54

Then we subtract: -12.706

8 0

3 years ago

The equation is y = -5(3^x)

balandron [24]

Answer:

Step-by-step explanation:

Since the number outside of the parentheses is -5, the negative factor means that the line is reflected across the x-axis.

3 0

3 years ago

Read 2 more answers

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

3 years ago

Math question down below

marusya05 [52]

18/27 can be reduced to 2/3 so the second option should be the correct answer

5 0

4 years ago

Read 2 more answers