the complete question is
If we add 5 to the denominator And subtract 5 from the numerator of a fraction ot reduces to 1/7. if we subtract 3 from the numerator and add 3 to its denominator ot reduces to 1/3. find the fraction.
Let
x/y-----------> the fraction
we know that
(x-5)/(y+5)=1/7------>7*(x-5)=(y+5)-----> y=7x-35-5----> y=7x-40----> equation 1
(x-3)/(y+3)=1/3----> 3*(x-3)=y+3----> y=3x-9-3----> y=3x-12------> equation 2
equate equation 1 and equation 2
7x-40=3x-12-----> 7x-3x=40-12------> 4x=28-----> x=7
y=3x-12------> y=3*7-12-----> y=9
x/y=7/9
the answer is
the fraction is 7/9
First you would have to find the distance it's going per hour.

You will then get the answer of 200 m/hr. You can then plug in 200 m/hr to find how far the jet could fly in 10 hours

You're final answer should be 2,000 miles
<u>Given</u>:
Given that O is the center of the circle.
The radius of the circle is 3 m.
The measure of ∠AOB is 30°
We need to determine the length of the major arc ACB
<u>Measure of major ∠AOB:</u>
The measure of major angle AOB can be determined by subtracting 360° and 30°
Thus, we have;


Thus, the measure of major angle is 330°
<u>Length of the major arc ACB:</u>
The length of the major arc ACB can be determined using the formula,
<u></u>
<u></u>
Substituting r = 3 and
, we get;



Thus, the length of the major arc ACB is 5.5π m
Answer: 4/15
Step-by-step explanation:
1/3+2/5 change it to 5/15+6/15=11/15 4/15 left of the lawn