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3 years ago

The change in direction of all free-moving objects ?

1 answer:

7 0

Moving in a direction is called having a "velocity". A velocity is just having a speed, but only in one direction. Because of a thing called "Newton's First Law", in order to change the speed or direction of an object, it must be accelerated, which is a fancy way of saying it's velocity must change with respect to time, meaning that for every second it travels while be accelerated, its velocity will change by this much, either in speed or direction or both. Due to "Newton's Second Law", and acceleration is gained by applying a force. Using the equation "F = ma" where F is force applied, m is mass of the object, and a is the acceleration of the object. This means that it is harder to move things with more mass.
Specifically relating to change in direction, force is also a thing which has a direction. A force can be any size, and also have any direction. When a force is applied in a certain direction, the acceleration of the object will be in the same direction of the force.

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Consider the following system at equilibrium where H° = 111 kJ/mol, and Kc = 6.30, at 723 K.

Rashid [163]

Answer:

1) The value of Kc:

C. remains the same.

2) The value of Qc:

A. is greater than Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium.

4) The concentration of N2 will:

B. decrease.

Explanation:

Hello,

In this case, by means of the Le Chatelier's principle which is based on the shift a chemical reaction could have under some modifications, we have:

1) The value of Kc:

C. remains the same, since it just depend the reaction's thermodynamics as it is computed via:

$ln(K)=\frac{\Delta _RG}{RT}$

2) The value of Qc:

A. is greater than Kc, since the reaction quotient is:

$Qc=\frac{[N_2][H_2]^3}{[NH_3]^2}$

Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium, since ammonia was withdrawn and should be regenerated to reach the equilibrium.

4) The concentration of N2 will:

B. decrease, since less reactant is forming the products.

Best regards.

8 0

4 years ago

Read 2 more answers

Find the mass of 3.00 mol of acetic acid, C2H4O2.

Alexeev081 [22]

Molar mass

C₂H₄O₂ = 60.0 g/mol

n = mass / molar mass

3.00 = mass / 60.0

m = 3.00 * 60.0

m = 180 g of <span>C₂H₄O₂

hope this helps!</span>

5 0

3 years ago

When the equal molar amounts of of both the acid and the base were reacts, what happened in the reaction?

Advocard [28]

It is going to be reaction of neutralization, and water and salt will be formed. If acid and base are strong, the reaction of the solution should become neutral.

3 0

4 years ago

A solution is made by adding 29.1 mL of concentrated perchloric acid ( 70.5 wt% , density 1.67 g/mL ) to some water in a volumet

Lera25 [3.4K]

Answer:

The concentration of the solution is 1.364 molar.

Explanation:

Volume of perchloric acid = 29.1 mL

Mass of the solution = m

Density of the solution = 1.67 g/mL

$m=1.67 g/mL\times 29.1 mL=48.597 g$