Answer:
Sulfate = tetrahedral
Explanation:
N° Geometry Formula
2 linear AX2
3 trigonal-planar AX3 or AX2E
4 tetrahedral AX4/AX3E/AX2E2
a) Nitrate = NO3-
⇒ AX3
⇒ bond angles = 120°
⇒ Coordination number = 3
⇒ Trigonal planar
b) Sulfate = SO42-
The central S
-atom has four electron domains. It has no lone pairs, so the electron geometry and the molecular geometry are tetrahedral.
⇒AX4
⇒ bond angles = 190.5°
⇒Coordination number = 4
⇒Tetrahedral
c) Chlorate = ClO3-
In ClO3-, the central atom is a Chlorine.
It has 7 valence electrons. The three oxygen form a double bond giving three bond pairs. The remaining two electrons make a lone pair. The total of 4 electron pairs shows that the molecule is sp3 hybridised.
The shape of sp3 hybrid molecule is a tetrahedral. But there is a lone pair. So, the geometry is <u>pyramidal</u>.
⇒AX4
⇒ bond angles = 190.5°
⇒Coordination number = 3
⇒pyramidal
Diffference between tetrahedral and pyramidal is that tetrahedral no has a lone pair, and has 4 atoms bonded to the central atom, while pyramidal has 1 lone pair and 3 atoms bonded to the central atom.
Sulfate has a tetrahedral geometry, which is a pyramidal structure
What happens in the artificial transmutation is that the nucleous is bombarded with high energy particles which we can describe as kinetic energy and the idea for them is to induce what we call transmutation. Also what happens is that the high energy particles are accelerated. One of the examples is when nitrogen is transformed into hydrogen by combining its nucleous with an alpha particle
Because it is held together by weak forces so no much energy is needed to break the bond
Answer:
We need 375 milliliters of 0.100 M NaHCO3 solution
Explanation:
Step 1: Data given
Initial molarity NaHCO3 = 0.100 M
Volume prepared solution = 750.0 mL
Molarity prepared solution = 0.05 M
Step 2: Calculate initial volume
C1*V1 = C2V2
⇒with C1 = the initial concentration = 0.100 M
⇒with V1 = The initial volume = TO BE DETERMINED
⇒with C2 = the new concentration = 0.0500M
⇒with v2 = the new volume = 750.0 mL = 0.750 L
0.100 M * V1 = 0.0500 M * 0.750 L
V1 = (0.0500M * 0.750L)/0.100 M
V1 = 0.375 L = 375 mL
We need 375 milliliters of 0.100 M NaHCO3 solution
D because 0 is always ignorant in significant figures. hope that helps:)
