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drek231 [11]
3 years ago
10

I need helpppp plzzzz

Chemistry
1 answer:
Inessa [10]3 years ago
8 0

Answer:

at first i would like to tell which class

Explanation:

125000 is the answwr

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How many grams of KO2 are needed to form 8.0 g of O2?
dem82 [27]
Using the atomic weights, K = 39, O=16 so KO2= 39+32=71. So K=39/71= 0.549 of KO2 and O2=32=0.45KO2 and O2=8g and 0.45KO2=8g so KO2=8/0.45=17.77g. So to check, K=0.549 x 17.77g=9.76 and so K+O2= 9.76+8g=17.76.
4 0
4 years ago
Read 2 more answers
How are the graphs of the sine function and the cosine function different?
Zielflug [23.3K]
They are different by a phase shift of pi/2
3 0
3 years ago
A19.0g sample of brass, which has a specific heat capacity of 0.375·J*g^−1°C−, is dropped into an insulated container containing
djverab [1.8K]

Answer:

The final temperature is 20.3 °C

Explanation:

Considering that:-

Heat gain by water = Heat lost by brass

Thus,  

m_{water}\times C_{water}\times (T_f-T_i)=-m_{brass}\times C_{brass}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

m_{water}\times C_{water}\times (T_f-T_i)=m_{brass}\times C_{brass}\times (T_i-T_f)

For water:

Mass = 300.0 g

Initial temperature = 20.0 °C

Specific heat of water = 4.184 J/g°C

For brass:

Mass = 19.0 g

Initial temperature = 81.7 °C

Specific heat of water = 0.375 J/g°C

So,  

300.0\times 4.184\times (T_f-20.0)=19.0\times 0.375\times (81.7-T_f)

1255.2T_f-25104=582.1125-7.125T_f

1262.325T_f=25686.1125

T_f = 20.3\ ^0C

<u>Hence, the final temperature is 20.3 °C</u>

6 0
3 years ago
Why the is ratio of magnesium ions to chloride ions in MgCl2 is 1:2?
Monica [59]
You should read up on Proust's law, better known as the Law of Definite Proportions. This is a chemical law that defines your question more generally, on why the ratio of elements and ions are always fixed.

Basically, this compound Magnesium(II) Chloride is MgCl2 because it has the same number of protons, neutrons, and electrons all the way. This defines the properties of the compound or atom. 
5 0
3 years ago
What is the molality of a solution containing 3. 0 moles of nacl and 100. 0 moles of water?
Mama L [17]

The molality of a solution containing 3. 0 moles of NaCl and 100. 0 moles of water is 30 mol/kg.

The number of moles of solute in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality. Mole per kilogram of solvent is the SI unit for molality.

Given:

3.0 moles of NaCl in 100 moles of water.

To find:

The molality of the solution

The moles of solute (NaCl) = 3.0 moles

The mass of solvent (water) = 100 moles (0.1 kg/mol)

Molality of a solution = Number of Moles of solute/ Mass of solvent(kg)

                                 = 3.0 moles/0.1 kg/mol

                                 = 30 mol/kg

To know more about Molality refer:

brainly.com/question/20354433

#SPJ4

                                           

4 0
2 years ago
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