Answer:
For 100 miles he uses 3.571 gallons of gasoline.
In equation form it is y/x*100
Step-by-step explanation:
Unitary Method
He travels 28 miles per gallon of gasoline.
For 1 mile he uses 1/28 gallons
For 100 miles he uses 1/28 * 100= 100/28= 3.571 gallons of gasoline.
Let x be the miles and y be the gallons of gasoline used to travel x miles.
Then for 1 mile the gallons of gasoline used will be y/ x gallons.
For 100 miles the gallons of gasoline used will be y/x *100 gallons.
In equation form it is y/x*100 gallons for 100 miles where x is the number of miles and y is the amount of gallons.
Answer:
≈ 6 units
Step-by-step explanation:
Calculate the distance d using the distance formula
d =
with (x₁, y₁ ) = F(2, 11) and (x₂, y₂ ) = G(5, 16)
d =
=
=
= ≈ 6 ( to the nearest whole number )
Answer:
The range of values likely to contain the true value of the population parameter is between 44% and 52%.
Step-by-step explanation:
Confidence interval concepts:
A confidence interval has two bounds, a lower bound and an upper bound.
These bounds are dependent of the sample mean and of the margin of error.
The lower bound is the sample mean subtracted by the margin of error, while the upper bound is the margin of error added to the sample mean.
The confidence interval is likely to contain the true value of the population parameter.
In this question:
Sample mean: 48%
Margin of error: 4%
48 - 4 = 44%
48 + 4 = 52%
The range of values likely to contain the true value of the population parameter is between 44% and 52%.
Answer:
hope it will help uh.....
Okay so just put the 4 in for x
and multiply