Classical activation should lead to an effective immune response against pathogens.
<h3>What is the classical activation pathway?</h3>
This is the most common pathway in the immune system.
<h3>What does classical activation imply?</h3>
- This is triggered by specific antibody complexes that react to a potential pathogen.
- A set of proteins and specialized cells are activated to attack the pathogen.
- A membrane attack complex is created.
<h3>What is the outcome?</h3>
The desirable outcome of this system is an effective immune response against pathogens such as viruses and bacteria.
Learn more about pathogens in: brainly.com/question/13873423
Answer:
12 pints
Step-by-step explanation:
There are 24 students & each one gets 1 cup, so you will need 24 cups total. There are 2 cups in a pint. You divided the 24 cups you need by 2 cups in a pint to get the answer of 12 pints.
You can double check: 12 pints converted to cups (2 cups in a pint) is 12 x2 = 24 cups
Answer:
C
Step-by-step explanation:
Since the vertex is 2,1, that's the only equation that works for it. The 2 has to be the opposite, so -2, and the 1 stays 1.
Answer:
(1,- 1.5)
Step-by-step explanation:
Sana po makatulong yan po sagot
Hope it help
Answer:
5.48% of the people in line waited for more than 28 minutes
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean waiting time of 20 minutes with a standard deviation of 5 minutes.
This means that 
What percentage of the people in line waited for more than 28 minutes?
The proportion is 1 subtracted by the p-value of Z when X = 28. So



has a p-value of 0.9452.
1 - 0.9452 = 0.0548.
As a percentage:
0.0548*100% = 5.48%
5.48% of the people in line waited for more than 28 minutes