Answer:
0
Step-by-step explanation:
A horizontal line has a slope of zero and a vertical line has an undefined slope
Answer: Approximately d = 208.72
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Work Shown:
Make sure your calculator is in radian mode
A quick way to check is to compute cos(pi) and you should get -1
cos(angle) = adjacent/hypotenuse
cos(x) = 200/d
cos(0.29) = 200/d
d*cos(0.29) = 200
d = 200/cos(0.29)
d = 208.715135166392 which is approximate
d = 208.72
I rounded to two decimal places since x is rounded in that manner as well. Round however else you need if your teacher instructs.
<span>points (6,10)
</span>y = -x
x + y = 0
distance = lax1 + by1 + cl/√(a^2 + b^2)
= l1(6) + 1(10) + 0l/√(1^2 + 1^2)
= l6 + 10 + 0l/√(1 + 1)
= l16l/√2
= 16/√2
= 8 .2/√2
= 8 . √2.√2/√2
= 8√2
Answer:
the answer is 479.
Step-by-step explanation:
to make it simpler, pretend you start from 1. 1,7,so on. multiply six by 79, to get 474. but because you are starting from 5 and not 1, you have to add 5 on.
sorry im super bad at math so this might be wrong
Answer:
Step-by-step explanation:
I attached an image to aid the understanding of the question.
Looking at the image, we see that the 8 shaded parts are congruent, as affirmed in the question as well. And we are told that T = 3, this implies that the area of the square with T as it's side is 9ft². Since all the 8 squares are congruenrt, it means each square has its area to be 9. Therefore, the total area of the 8 shaded squares will be:
It remains the area of the shaded square with side S.
From the question, we have the following ratio:
![\frac{9}{S} = \frac{S}{T}[\tex]But[tex]\frac{9}{S} = \frac{S}{3}[\tex]Multiplying through by 3S we have27 = S² and this gives:[tex]S = \sqrt{27} = 3\sqrt{3}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7BS%7D%20%3D%20%5Cfrac%7BS%7D%7BT%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3EBut%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cfrac%7B9%7D%7BS%7D%20%3D%20%5Cfrac%7BS%7D%7B3%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3EMultiplying%20through%20by%203S%20we%20have%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E27%20%3D%20S%C2%B2%20and%20this%20gives%3A%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%5Btex%5DS%20%3D%20%5Csqrt%7B27%7D%20%3D%203%5Csqrt%7B3%7D)
I did not add ± because length is always positive, so the case of negative is eliminated.
Now the areas of S is 
Therefore, the total area of the shaded squares is
