DF congruent to AC and EF is common side
Answer:
13y= x + 59
Step-by-step explanation:
gradient= y² - y¹ / x²- x¹
=5 - 4 / 6- -7
= 1/ 13
<h3>equation of line:
<u>y=mx+c</u></h3>
x y
point (6,5)
<u>substitute</u>:
5= <u> </u><u>1</u><u> </u> (6) + c
13
c = 5 -<u> </u><u>6</u><u> </u>
13
= <u>5</u><u>9</u>
13
y=mx+c
13y= 1x + 59
Answer:
y=5/3 is the only real solution
Step-by-step explanation:
Solve for y over the real numbers:
11 y^2 - 19 y - 10 = -4 y^2
Add 4 y^2 to both sides:
15 y^2 - 19 y - 10 = 0
The left hand side factors into a product with two terms:
(3 y - 5) (5 y + 2) = 0
Split into two equations:
3 y - 5 = 0 or 5 y + 2 = 0
Add 5 to both sides:
3 y = 5 or 5 y + 2 = 0
Divide both sides by 3:
y = 5/3 or 5 y + 2 = 0
Subtract 2 from both sides:
y = 5/3 or 5 y = -2
Divide both sides by 5:
Answer: |
| y = 5/3 or y = -2/5
