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Nana76 [90]
3 years ago
10

What is the answer for number 6

Mathematics
2 answers:
Helga [31]3 years ago
7 0
Inches             Centimeters
2                            5
4                            10
6                            15.24
8                            20.32
1                            2.54
9.84                        25
Ilya [14]3 years ago
6 0
Inches: 2 4 6 8 1 21
centimeters: 8 10 12 14 7
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You want to make 3 pairs of earrings that are in the shape of isosceles triangles. Each earring will have a base of 2 cm. The wi
son4ous [18]

Answer:

The length of each of the other two sides would be  3.1 cm

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A. 3.1 cm

B. 3.2 cm

C. 4.2 cm

D. 6.1 cm

we know that

An isosceles triangle has two equal sides and two equal interior angles

Let

x -----> the length of each of the two equal sides in the isosceles triangle

The perimeter of one isosceles triangle is equal to

P=2x+2

Remember that

To maximize the use of the wire, the perimeter of 6 earrings (3 pairs of earrings) must be equal to 50 cm

so

6(2x+2)=50

Solve for x

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therefore

The length of each of the other two sides would be  3.1 cm

7 0
3 years ago
Write the expression for when you translate the graph of y = | 1/2 x−2 |+3 a) one unit up, b) one unit down, c) one unit to the
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Answer:

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  b) y = |x/2 -2| +2

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Step-by-step explanation:

To translate the function f(x) by (h, k) in the (right, up) direction, you transform it to ...

  g(x) = f(x -h) +k

<u>a) one unit up</u>

Add 1 to the function value.

  y=\left|\dfrac{x}{2}-2\right|+3+1\\\\\boxed{y=\left|\dfrac{x}{2}-2\right|+4}

<u>b) one unit down</u>

Subtract 1 from the function value.

  y=\left|\dfrac{x}{2}-2\right|+3-1\\\\\boxed{y=\left|\dfrac{x}{2}-2\right|+2}

<u>c) one unit left</u>

Replace x with x-(-1).

  y=\left|\dfrac{x-(-1)}{2}-2\right|+3\\\\\boxed{y=\left|\dfrac{x+1}{2}-2\right|+3}

<u>d) one unit right</u>

Replace x with x-1.

  \boxed{y=\left|\dfrac{x-1}{2}-2\right|+3}

7 0
3 years ago
Please help!! This topic is incredibly confusing and assistance is very much needed &amp; appreciated! Thanks :)
Artyom0805 [142]
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