Problem 1
We'll use the product rule to say
h(x) = f(x)*g(x)
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
Then plug in x = 2 and use the table to fill in the rest
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)
h ' (2) = 2*3 + 2*4
h ' (2) = 6 + 8
h ' (2) = 14
<h3>Answer: 14</h3>
============================================================
Problem 2
Now we'll use the quotient rule

<h3>Answer: -2/9</h3>
============================================================
Problem 3
Use the chain rule

<h3>Answer: 12</h3>
Factor x^4 -4x^3 -4x^2 +36x-45
Answer:
<h2>(x+3)(x−3)(x^2−4x+5)</h2>
Answer:
needing this toooooo
Step-by-step explanation:
Answer:
7.9
Step-by-step explanation:
Multiply both sides of the equation by 11. This cancels out the fraction so 11 * 5/7 = x
lmk if I misunderstood the question or need to elaborate