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Gre4nikov [31]
3 years ago
15

Help me ASAP for this question

Mathematics
1 answer:
ivann1987 [24]3 years ago
4 0

Answer: Y= 2x

Step-by-step explanation:

1 x 2 = 2

3.4 x 2 = 6.8

5 x 2 = 10

7 x 2 = 14

So. Y = 2x

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ROOTS AND CUBES<br> Can someone please help me answer all 4 following?
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NOTES:

  • squared (²) means multiply that number by itself 2 times
  • cubed (³) means multiply that number by itself 3 times
  • square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
  • cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical

Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

   \bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}

=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

=(7 - 2)\times \dfrac{1}{5}+9

=5 \times \dfrac{1}{5}+ 9

= 1 + 9

= 10

***************************************************************************************

8² = 8 · 8 = 64                                     11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125                               3³ = 3 · 3 · 3 = 27

\sqrt{1600}=\sqrt{40\cdot 40}=40                       \sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4

\sqrt{144}=\sqrt{12\cdot 12}=12                            \sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20

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The answer to this is d
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For the graph Y equals 1 find slope of a line that is perpendicular to it in the slope of a line parallel to it
marishachu [46]

Answer:

The answer is Undefined (∞).

Step-by-step explanation:

The line y = 1 has a slope of 0, and the line parallel to it, for instance, y = 3, has the same slope, m1 = 0. For the slope of the line perpendicular to that parallel line is m2 = -1/m1, which is -1/0 = ∞

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