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Alchen [17]
3 years ago
7

Each set of (x, y) values represent a set of equivalent ratios. Find the ratio of x to y for each set to determine which set des

cribes the proportional relationship: 66 ounces of peanuts to 89.1 ounces of walnuts.
Mathematics
1 answer:
Pavel [41]3 years ago
3 0

Answer:

I believe it is 60-10=x because it says she purchased it with 60$ but recieved 10$ in change causing the amount we dont know to be a variable such as "x"

Step-by-step explanation:

I believe it is 60-10=x because it says she purchased it with 60$ but recieved 10$ in change causing the amount we dont know to be a variable such as "x"

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Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive
PtichkaEL [24]
Looks like the PMF is supposed to be

\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65

Next,

\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25

\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5

\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2
\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5
\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}

If Y=X^2+1, then X^2=Y-1\implies X=\sqrt{Y-1}, where we take the positive root because we know X can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that Y can take on the values 1^2+1=2, 2^2+1=5, and 5^2+1=26. At these values of Y, we would have the same probability as we did for the respective value of X. That is,

\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}

Part (5) is incomplete, so I'll stop here.
8 0
3 years ago
2.34 x 10^65   + 9.2 x10^66  
vivado [14]

Answer:

9.434 X 10^66

Step-by-step explanation:

2.34 X 10^65  +  9.2 X 10^66    (First, you have to manipulate the exponents to bring them to the same index, i.e. the same power)

We can say that 2.34 X 10^65 = 0.234 X 10^66

Now that the indexes are equivalent, we can proceed to add the two bases together.

0.234 X 10^66  +  9.2 X 10^66

= (0.234  +  9.2) X 10^66

= 9.434 X 10^66

3 0
3 years ago
HELP ASAP PLS PLS PLS !
Maslowich

Answer:

(b) the unknown angle is 80°

Step-by-step explanation:

The unkown angle is:

[2(x-10)]°

Substituting "x" by 50 (part a)

[2(50-10)]°=[2(40)]°=80°

6 0
3 years ago
Which two numbers have a mean of 10 and a range of 4
Elden [556K]

Answer:

12 and 8

Step-by-step explanation:

set two numbers as x and y

mean of 10   →   x+y/2=10

range of 4    →   x-y=4

     x+y=20

+    x-y=4

____________

      2x=24, x=12  

      12-y=4, y=8        

6 0
3 years ago
Hello, could anyone help me on part A and part B
solniwko [45]

Answer:

9 answer ok like floow on

7 0
3 years ago
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