Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
then, Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9) (sec²Ф will have a negative value, because Ф is in the sec Ф=-5/3 third quadrant).
cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5
Therefore:
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2
Answer: tan (Ф/2)=-2; when tan (Ф)=4/3
Answer:
A ; 23rd century
Step-by-step explanation:
Here, we want to select which of the options is next to have a descending year.
Since all are in the same century i.e 20-something, we do not have an issue with the first digit.
What we need to work on is the last three digits;
We can have 2210, we can have 2321, we can have 2432, we can also have 2543 and so on.
The most recent of all these is the year 2210, so what century does this belong?
Kindly note that, the years 2001-2100 belong to the 21st century.
The years 2101-2200 belong to the 22nd century while the years 2201-2300 belong to the 23rd century
The year we are looking to place is the year 2201 and thus belongs to between 2201-2300 which is the 23rd century
A i did this and i got a good grade
Answer:
40
Step-by-step explanation:
Any solution x will mod 23 will also have x+23n as a solution, for some integer n. Since 900/23 = 39 3/23, we know there are 39 or 40 three-digit integers of this form.
As it happens, 100 is the smallest 3-digit solution. So, there are 40 three-digit numbers that are of the form 100 +23n, hence 40 solutions to the equation.
_____
The equation reduces, mod 23, to ...
10x = 11
Its solutions are x = 23n +8.
Answer:
2
Step-by-step explanation:
Thats your answerrrrrr
