Answer: 129.81 m, roughly 130 m
Step-by-step explanation: Let me know if you need an explanation.
Answer:
a) The mass is released at t = 0 when h is minimum. Half a cycle later h reaches its maximum and another half a cycle it reaches its minimum again. Hence over one cycle, h varies with t as follows:
b) According to the graph obtained in part a), h(t) could be modeled by a cosine function shifted (translated) vertically up and horizontally to the right. Hence
Step-by-step explanation:
Alright, let's factor this to get the answer.
3k^2-10k+7
To find the factors, we want to think "What will add up to -10, and multiply to (+)7?"
Because the leading coefficient is 3, we know that we can take one factor of 7 and multiply it by 3.
Thus, this factors to
(3k-7)(k-1)
(if you FOIL it it should come out to be the original equation)
From this, set both of those [(3k-7) and (k-1)] equal to zero and solve
3k-7=0
3k=7
/3
k=7/3
or
k=1
Answer:
1cm:100cm
Step-by-step explanation:
You have to convert the ratio into the same unit (I chose cm). If there are 100cm in a metre, there will be 300cm in 3m.
That leaves you with the ratio 3cm:300cm. To simplify, divide both sides by three leaving you with 1cm:100cm
