Answer:
d.
Step-by-step explanation:
if x varies directly as y,
x = ky
8 = 12k
12k = 8
k = 8/ 12
k = 2/3,
x = 2/3 y
now substitute the value of any of the numbers of each pair, and check if it works:
for e.g, find x when y = 15
x = 2/3y
x = 2/3 × 15
x = 10
since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .
ii) x = 2/3y
x = 2/3 × 3, when y = 3
x = 2
hence, this is also a possible pair of x and y values.
iii) x = 2/3y
x = 2/3 × 9 when y = 9
x = 6
again, a possible pair of x and y values.
iv) x = 2/3y
x = 2/3 × 20 when y = 20
x = 40/3
here, when y = 20, x is not 15. it is 40/3.
thus, it can be determined that this is not a possible pair of x and y values.
please try to understand and have a great day!
If two triangles are similar, then their side lengths are proportional.
RS / JK = RT / JL
5 / x = 4 / 7
4x = 35
x = 35/4 = 8.75
RT / JL = TS / LK
4 / 7 = 6 / (y + 2)
42 = 4(y + 2)
42 = 4y + 4
4y = 38
y = 38/4 = 9.5
LK = 9.5 + 2 = 11.5 cm
JK = x = 8.75
Hope this helps!
