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Vlad [161]
3 years ago
8

Please help i have to go to school in 40 min

Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0
2. 24/10 (if need to simplify it's 12/5)
3. 8/5 (can't simplify more)
5.60/5 (simply 12/1 = 12)
6.21/10 (can't simplify)
Afina-wow [57]3 years ago
6 0
5: 12, 6: 2 and 1/10, 2: 2 and 2/5, 3: 1 and 3/5 to figure it out do whole number x numerator divided by denominator
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A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med
Troyanec [42]
The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test -  No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is  \frac{0.0396}{0.0396+0.0096}= \frac{33}{41}

The probability of someone picked at random has cancer given that test result indicates no cancer is \frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}

7 0
3 years ago
A deck of cards with four suits; hearts, diamonds, spades, and clubs. you pick one card, put it back and thennpick another card.
Llana [10]

1. First, let us find the probability that the first card is a diamond.

Now, since we are given that there are four suits and there are, assumably, an equal number of cards in each suit, we can say that the probability of choosing a diamond card is 1/4. We can also write this out as such, where D = Diamond:

Pr(D) = no. of diamond cards / total number of cards

There are 52 cards in a deck, and 13 cards of each suit, thus:

Pr(D) = 13/52 = 1/4

2. Now we need to calculate the probability of not choosing a diamond as the second card.

In many cases, when given a problem that requires you to find the probability of something not happening, it may be easier to set it out as such:

Pr(A') = 1 - Pr(A)

ie. Pr(A not happening, or not A) = 1 - Pr(A happening, or A)

This works because the total probability is always 1 (100%), and it makes sense that to find the probability of A not happening, we take the total probability and subtract the probability of A actually happening.

Thus, given that we have already calculated that the probability of choosing a Diamond is 1/4, we can now set this out as such:

Pr(D') = 1 - Pr(D)

Pr(D') = 1 - 1/4

Pr(D') = 3/4

3. Now we come to the final step. To find the probability of something and then something else happening, we must multiply the two probabilities together. Thus, given that Pr(D) = 1/4 and Pr(D') = 3/4, we get:

Pr(D)*Pr(D') = (1/4)*(3/4)

= 3/16

Thus, the probability of choosing a diamond as the first card and then not choosing a diamond as the second card is 3/16.

7 0
3 years ago
Can someone please help me with these 2 math questions!
kondaur [170]

Step-by-step explanation:

The additional information is GD ≅ CD

 The additional information is ∠LQR ≅ ∠PQR

SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ  

7 0
3 years ago
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First, we have to find the rate:
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2 years ago
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SashulF [63]

Answer:

Whats F five is that a point or something???

Step-by-step explanation:

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3 years ago
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