No. When you plug in x and y you get 2=3
Answer:
Answer:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Where xx is the number of small boxes sent and yy is the number of large boxes sent.
Step-by-step explanation:
Let be xx the number of small boxes sent and yy the number of large boxes sent.
Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:
20x+30y=28020x+30y=280
According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:
y=4xy=4x
Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
You start at 0 on the unit circle the cos of 0 =1, but at cos 0 there is no angle at all so there is no y value so at cos 0 y=0, 180 is the opposite direction of the starting point which is 0 so the x value of cos180= -1 but there is still no upward or downward angle ie.. y value. so the y value = 0 at 0 and 180. answer is 0
Answer:
5/6 books
Step-by-step explanation:
We know that Mark read 2 1/2 books last week. This week, he read a bit more with 3 1/3 books.
To find how many more books he read, we must subtract 2 1/2 from 3 1/3:
3 1/3 - 2 1/2
Let's convert these into improper fractions first:
3 1/3 = (3 * 3 + 1) / 3 = 10/3
2 1/2 = (2 * 2 + 1) / 2 = 5/2
Now, we have:
10/3 - 5/2
In order to subtract these, we must find a common denominator. For 2 and 3, the LCM is 6, so we can use that as our common denominator:
10/3 * 2/2 = 20/6
5/2 * 3/3 = 15/6
Finally, we have:
20/6 - 15/6 = (20 - 15) / 6 = 5/6 books
Answer:
x > -2
Step-by-step explanation:
Solve the inequality -4x < 8 using inverse operations. If you divide or multiply by a negative, flip the inequality sign.
x > -2
