It is the first one ...w= 3z+2
The calories in a cup of low fat milk is 102 calories and the calories in a cup of milk in skim 86 calories .
<h3>What are the two simultaneous equations that can be sued to represent this question?</h3>
2/3l + 1/2s = 111
4l + 3s = 666 equation 1
l + s = 188 equation 2
Where:
l = calories in the low fat milk
s = calories in the skim milk
<h3>What is the calories in the skim milk?</h3>
Multiply equation 2 by 4
4l + 4s = 752 equation 3
Subtract equation 1 from 3
s = 86
<h3>What is the calories in the low fat milk?</h3>
Substitute for s in equation 2
l + 86 = 188
l = 188 - 86
l = 102
To learn more about simultaneous equations, please check: brainly.com/question/25875552
Answer: One DVD is $12 and one book is $1
Step-by-step explanation:
Let the DVD be d and the book be b.
Case 1:
3d + 4b = $40.......(1)
Case 2:
1d + 6b = $18........... (2)
In this equations above, I intend to eliminate variable d, so I'm going to multiply the coefficient of d in (1) to multiply (2)
3 × (1d + 6b = 18)
3d + 18b = 54........ .(3)
Then, subtract (1) from (3)
3d + 18b = 54
- ( 3d + 4b = 40)
3d - 3d + 18b - 4b = 54 - 40
0 + 14b = 14
b = 14/14
b = 1.
Then substitute 1 for b in (2)
1d + 6(1) = 18
d + 6 = 18
d = 18 - 6
d = 12.
(d,b) = (12,1)
MISSING DETAILS
Yoko's fish tank has 17 liters of water in it. She plans to add 5 liters per minute until the tank has at least 57 liters. What are the possible numbers of minutes Yoko could add water?
Answer:
Minutes = 8 minutes
Step-by-step explanation:
Topic: Inequality
Given:
Available Size of water = 17 liters
Increment = 5 liters/minute
Size of water needed = At least 57 liters
Putting the above together, as have
17 + 5m > 57
where m represents total minutes and > represent at least
Solving the Inequality
5m > 57 - 17
5m > 40 ------ Divide through by 5
5m/5 > 40/5
m > 8
So, Yoko will need to add water for at least 8 minutes before she fills her tank to 57 liters.
