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3 years ago

How would you write - 4.5 as a fraction

Mathematics

2 answers:

Minchanka [31]3 years ago

8 0

this should be the right answer 9/2

Helga [31]3 years ago

5 0

You would write it as -4 1/2

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In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per

Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, $P_0=450,000$

Growth rate is, $r=5\%=0.05$

Final population is, $P=700,000$

A population growth is an exponential growth and is modeled by the following function:

$P=P_0(1+r)^x$

Taking log on both sides, we get:

$\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}$

Plug in all the given values and solve for 'x'.

$x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10$

So, for $x > 9.13$ , the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0

3 years ago

What is the distance between -10 and six on a number line

Mkey [24]

Answer:

10+6=16

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

ASAP !!

brilliants [131]

Answer:

Step-by-step explanation:

8 0

3 years ago

elena55 [62]

Answer:

C. 0.300 s.

11 + x

Step-by-step explanation:

brainest plz

4 0

3 years ago

Read 2 more answers

1. Which would be a more helpful for solving the system: adding the two equations or subtracting

ira [324]

Answer:

1) Subtracting one from the other

2) x = 0.375 and y = 0.125

Step-by-step explanation:

Equation 1 :

$\frac{2x+1}{2y}=7\\\\$

Equation 2:

$\frac{6x-1}{2y}=5$

To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,

$\frac{2x+1}{2y} =7\\\\2x+1=14y\\\\Multiplying\ Equation\ 1\ with\ 6\\\\12x+6=84y$

Now for the second equation:

$\frac{6x-1}{2y}=5\\\\6x-1=10y\\\\Multiplying\ equation\ 2\ with\ 2 \\\\12x-2=20y$

Now subtracting equation 2 from equation 1

$12x+6=84y\\\\12x-2=20y\\\\Subtracting\ leads\ to\\12x-12x+6-(-2)=84y-20y\\0+8=64y\\8=64y\\8/64=y\\0.125=y$

now insert this value of y into any equation

lets insert it into equation 1

$\frac{2x+1}{2y} =7\\\\2x+1=14y\\2x+1=14(0.125)\\2x+1=1.75\\2x=1.75-1\\2x=0.75\\x=0.75/2\\x-0.375$

5 0

3 years ago