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2 years ago

7

I need help on 8 9 and 10

1 answer:

Lerok [7]2 years ago

4 0

9. x + (y - 3 - 4x + 2( 3x - (-y - 1) + 2y) - 3x)

= x + (y - 3 - 4x + 2 (3x + y - 1) + 2y - 3x)
= x + (y - 3 - 4x + 6x + 2y - 2 + 2y - 3x)
= (x - 4x + 6x - 3x) + (y + 2y + 2y) - (3+2)
= 0 + 5y - 5
= 5y - 5 (or simplified as 5(y-1)

10. 6 + (-a -3(b + 6(a - b)+4a) - 2b)
= 6 + (-a - 3(b + 6a - 6b + 4a) -2b)
= 6 + (-a - 3b + 18a - 18b + 12a - 2b)
= 6 + (-a + 18a + 12a) + (-3b - 18b - 2b)
= 6 + 29a - 23b

Lmk if it's wrong, I'll try to edit it.

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Help pls OOOFFIES AND ASAP

Nimfa-mama [501]

Answer:

it is

Step-by-step explanation:

0.75. or that's at least what Google told me

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2 years ago

Show that 2x +1 is a factor of 2x3 +5x2+4x+1 and factories completely

larisa [96]

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2 years ago

Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

$g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}$

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

$x-1\leq 0\Rightarrow x\leq 1$

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

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3 years ago

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Answer:

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Step-by-step explanation:

Differentiate H = 64t - 16t² to find an equation for velocity:

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2 years ago

A die is rolled twice. What is the probability of showing a 1 on the first roll and an even number on the second roll?

Ivan

Answer:

1/12

Step-by-step explanation:

Okay, so this will be a compound probability question because there are two parts to the question.

Firstly, a die has 6 sides, and there is only one chance of getting a 1, so the probability would be 1/6.

Furthermore, there are 3 different even numbers on a 6-sided die, so that is 3/6, which can be simplified to 1/2.

Now, because this is a compound probability, we have to multiply 1/2 and 1/6 together, which would give us our answer of 1/12.

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3 years ago

Read 2 more answers