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Alla [95]
4 years ago
8

Determine the quotient, q(x), and remainder, r(x) when

Mathematics
1 answer:
Vinvika [58]4 years ago
5 0
ANSWER

Quotient:

q(x) = 4 {x}^{2} + 3x + 2

Remainder:

r(x) = 3x + 1

EXPLANATION

The given functions are

f(x) = 12 {x}^{4} + 21 {x}^{3} + 31 {x}^{2} + 21x + 9

and

g(x) = 3 {x}^{2} + 3x + 4

We want to find the remainder and quotient when f(x) is divided by g(x).

We perform the long division as shown in the attachment.

The quotient is

q(x) = 4 {x}^{2} + 3x + 2

The remainder is

r(x) = 3x + 1

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Answer:

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Step-by-step explanation:

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3 years ago
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The general solution of tan(b·x) = 2, given that the smallest positive solution is x = 0.3, is presented as follows;

\mathbf{ x =0.3 +  \dfrac{n \cdot \pi}{b}}

The given smallest positive solution of tan (b·x) = 2 is x = 0.3

The general solution of tan (b·x + c) = m, is given as follows;

\mathbf{x = \dfrac{\alpha  - c}{b}  + n \cdot \dfrac{\pi}{b}}

α = arctan(m) = x₀

The minimum positive value of the general solution is therefore presented as follows;

x_{min \ positive} = \dfrac{\alpha  - c}{b}  + 0 \times \dfrac{\pi}{b} = \dfrac{\alpha  - c}{b}

\mathbf{x_{min \ positive} = \dfrac{\alpha  - c}{b}}

In the given function, tan (b·x), we therefore, have;

c = 0, m = 2,  \dfrac{\alpha  - c}{b} = 0.3

The general solution of tan(b·x) = 2, is therefore;

\mathbf{x =0.3 +  \dfrac{n \cdot \pi}{b}}

Learn more about the general solution of a sine function here:

https://brainly.in/question/1549935

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