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Leona [35]
3 years ago
5

Find the value of y- y^2=169

Mathematics
2 answers:
Blababa [14]3 years ago
6 0

Answer:

13

Step-by-step explanation:

square root y^2 = square root 169

so

y = 13

oksian1 [2.3K]3 years ago
6 0

Answer:

y=13

Step-by-step explanation:

y=square root of 169

y=13

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I dont understand how to do this precalc question
Alexeev081 [22]

Answer:

  • x-intercept:  (-0.1, 0)
  • Horizontal Asymptote: y = -3
  • Exponential <u>growth</u>

(First answer option)

Step-by-step explanation:

<u>General form of an exponential function</u>

y=ab^x+c

where:

  • a is the initial value (y-intercept).
  • b is the base (growth/decay factor) in decimal form:
    If b > 1 then it is an increasing function.
    If 0 < b < 1 then it is a decreasing function.
  • y=c is the horizontal asymptote.
  • x is the independent variable.
  • y is the dependent variable.

Given <u>exponential function</u>:

y=4(10)^x-3

<h3><u>x-intercept</u></h3>

The x-intercept is the point at which the curve crosses the x-axis, so when y = 0.  To find the x-intercept, substitute y = 0 into the given equation and solve for x:

\begin{aligned}& \textsf{Set the function to zero}:& 4(10)^x-3 &=0\\\\& \textsf{Add 3 to both sides}:& 4(10)^x &=3\\\\& \textsf{Divide both sides by 4}:& 10^x &=\dfrac{3}{4}\\\\& \textsf{Take natural logs of both sides}:& \ln 10^x &=\ln\left(\dfrac{3}{4}\right)\\\\& \textsf{Apply the power log law}:&x \ln 10 &=\ln\left(\dfrac{3}{4}\right)\\\\& \textsf{Divide both sides by }\ln 10:&x&=\dfrac{\ln\left(\dfrac{3}{4}\right)}{\ln 10} \\\\& \textsf{Simplify}:&x&=-0.1\:\:\sf(1\:d.p.)\end{aligned}

Therefore, the x-intercept is (-0.1, 0) to the nearest tenth.

<h3><u>Asymptote</u></h3>

An <u>asymptote</u> is a line that the curve gets infinitely close to, but never touches.

The <u>parent function</u> of an <u>exponential function</u> is:

f(x)=b^x

As<em> </em>x approaches -∞ the function f(x) approaches zero, and as x approaches ∞ the function f(x) approaches ∞.

Therefore, there is a horizontal asymptote at y = 0.

This means that a function in the form  f(x) = ab^x+c always has a horizontal asymptote at y = c.  

Therefore, the horizontal asymptote of the given function is y = -3.

<h3><u>Exponential Growth and Decay</u></h3>

A graph representing exponential growth will have a curve that shows an <u>increase</u> in y as x increases.

A graph representing exponential decay will have a curve that shows a <u>decrease</u> in y as x increases.

The part of an exponential function that shows the growth/decay factor is the base (b).  

  • If b > 1 then it is an increasing function.
  • If 0 < b < 1 then it is a decreasing function.

The base of the given function is 10 and so this confirms that the function is increasing since 10 > 1.

Learn more about exponential functions here:

brainly.com/question/27466089

brainly.com/question/27955470

6 0
2 years ago
1.) Which of the following expressions is the difference of two terms?
Step2247 [10]

Answer:

1.a

2.a

3.d

4.c

5.c

Step-by-step explanation:

sana makatulung po

8 0
3 years ago
Simplify: -6( 5 /3 x + 4)
yaroslaw [1]

Answer:

-10x-24

Step-by-step explanation:

-6(\frac{5}{3}x+4)

-6*\frac{5}{3}x+-6*4

-10x-24

8 0
3 years ago
Read 2 more answers
Ashley pounds 98 pounds one year ago .If she weight 112 pounds what is the percent increase in her weight ?
andreyandreev [35.5K]

Answer:

The increase to the nearest percent is 14%

Step-by-step explanation:

\frac{112 - 98}{98}  The percent of increase is the weight change over the original amount

.14285714285  To change a decimal to a percent, move the decimal two places to the right.

Rounded to the nearest percent is

14%

3 0
1 year ago
Can you name the trigonometric expression that is equivalent to the following expression 1/secant of x?
Arlecino [84]
The answer to your question is:  Yes, I can.


You haven't asked for the trigonometric expression, but here it is anyway:

The  <u>cosine</u>  function is the reciprocal of the secant function.
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