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alekssr [168]
4 years ago
7

Help me please and thank you!

Mathematics
1 answer:
Alina [70]4 years ago
7 0

Answer:

The first picture and 28.2 square units

Step-by-step explanation:

Equation: A+1/2ps

A = area of the base

p = perimeter of the base

s = slant height

3²+1/2(12)(3.2)=28.2

You might be interested in
25 units 5 units x units​
Sunny_sXe [5.5K]

Answer: It depends on the the question.

25 <u>square</u><u><em> </em></u>units would be 5 times 5 units.

25 <u>linear</u> units would be 5 units  plus 20 units.

Step-by-step explanation:

6 0
3 years ago
Find the value of x. Round your answer to the nearest tenth.
-Dominant- [34]

Answer:

b is the third line

\sin(58)  =  0.848

also sin(58)=22/b

0.848=22/b

b=(22/0.848)=25.9

\sqrt{22 ^{2} + 25.9^{2}  }  = 33.98

x=33.98

8 0
3 years ago
A man is standing on the bridge about to bungee jumps he weighs 54 kg the bridge is 67 meters high
olga nikolaevna [1]
Nevis Highwire, New Zealand – 134 meters. ...
Navajo Bridge, Arizona, US – 141.5 meters. ...
Kaivopuisto, Helsinki, Finland – 150 meters. ...
Bhote Kosi River, Nepal – 160 meters. ...
Altopiano di Asiago, Vicenza, Italy – 175 meters. ...
Niouc Bridge, Switzerland – 190 meters.
5 0
3 years ago
Assume that the weights of individuals are independent and normally distributed with a mean of 160 pounds and a standard deviati
Ilia_Sergeevich [38]

Answer:

a) \bf 0.3446^{25}=2.7095*10^{-12}

b) 3,624.25 pounds

Step-by-step explanation:

a)

Since 4300/25 = 172, in average every single person should weight 172 pounds to exceed the design limit.

The probability that one person weights 172 pounds or more is the area under the Normal curve with mean 160 pounds and standard deviation 30 pounds to the right of 172.

<em>In Excel and OpenOffice Calc, this value is found with the formula </em>

<em>=1-NORMDIST(172;160;30;1) </em>

<em> (NORMDIST(172;160;30;1) gives the area to the left of 172, so 1-NORMDIST(172;160;30;1) gives the area to the right of 172) </em>

and equals 0.3446

(see picture 1)

Hence, the probability that all the 25 people exceeds 172 pounds equals

\bf 0.3446^{25}=2.7095*10^{-12}

b)

Similarly, we must find a weight w such that if p is the area to the left of w, then  

\bf p^{25}>0.0001  

so  

\bf p=\sqrt[25]{0.0001}=0.6918

w would be the point such that the area under the Normal curve with mean 160 pounds and standard deviation 30 pounds to the right of w equals 0.6918.

<em>In Excel and OpenOffice Calc this is found with </em>

<em>=NORMINV(1-0.6918;160;30) </em>

and equals 144.97 pounds

(See picture 2)

and the design limit that is exceeded by 25 occupants with probability 0.0001 is 25*144.97 = 3,624.25 pounds

6 0
4 years ago
Whats the equation of the line?
Phantasy [73]

Answer: I believe it should be answer B

Step-by-step explanation: the x coordinate pairs with y and vice versa and if it’s positive you subtract is how I remember it.

3 0
3 years ago
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