Round 98,471 to the nearest ten thousands
1 answer:
You might be interested in
1. It's all about pattern matching, as a lot of math is.
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.
Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K
∠C ⇒ ∠L
AC ⇒ JL
BC ⇒ KL
2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS
3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.
Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.
Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K
∠C ⇒ ∠L
AC ⇒ JL
BC ⇒ KL
2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS
3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.
Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)
Answer:
66.7%
Step-by-step explanation:
Please find attached the complete question
Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.
For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.
probability that a randomly selected point within the circle falls in the white area = degree occupied by white area / sum of angles in a circle
sum of angles in a circle = 360
degree occupied by white area = sum of angles in a circle - sum of degrees of shaded area
360 - (60 + 60) = 240
240 / 360
convert to its simplest form by dividing by 120 = 2/3
2/3 x 100 = 66.7%
