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Montano1993 [528]
3 years ago
14

BRAINLIEST find the value of a^n b^n if n=3,a=100,and b=1/4

Mathematics
2 answers:
Bumek [7]3 years ago
5 0

Answer:

= (100)^3(1/4)^3

= 15,625  i think im not that good at math but i passed

Step-by-step explanation:

FinnZ [79.3K]3 years ago
3 0

Hi there! My name is Zalgo and I am here to help you out on this gracious day. If n=3, a=100 and b=1/4, the equation should look like "100^3 * 1/4^3". The answer would be 15625.

I hope that this helps! :D

"Stay Brainly and stay proud!" - Zalgo

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Answer:

P(B and V)=10%

Step-by-step explanation:To solve this poroblema we use the formula of combinations:

C(n,r)=(nr)=n!(r!(n−r)!)

Where n is the number of objects that can be chosen and you choose r from them.

There are 5 colors of shirts.

The number of shirts that can be made by combining 2 of the 5 possible colors is calculated as:

5C2= \frac{5!}{2!(5-2)!}

5C2=10

The number of shirts that can be made by combining 2 of the 2 possible colors (B) and (V) is calculated as:

2C2=1

Then the probability is:

P( B and V)= \frac{1}{10}

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\frac{2C2}{5C2}

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So here are 4 rules when it comes to exponents:

  1. When you raise a power to a power, you really just multiply the exponents: (x^m)^n=x^{m*n}
  2. When you multiply 2 exponents of the same base, you add the exponents together: x^m*x^n=x^{m+n}
  3. When you divide 2 exponents of the same base, you subtract the exponents: \frac{x^m}{x^n}=x^{m-n}
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<u>Part A:</u>

\frac{2x^3y^3}{4y^2}=\frac{1}{2}x^{3-0}y^{3-2}=\frac{1}{2}x^3y

<u>Part B:</u>

(\frac{x^{-8}}{y^{11}})^{-2}=\frac{x^{-8*-2}}{y^{11*-2}}=\frac{x^{16}}{y^{-22}}=\frac{x^{16}y^{22}}{1}=x^{16}y^{22}

<u>Part C:</u>

\frac{(2x^3)(x^4)^2}{8x^{11}}=\frac{(2x^3)(x^{4*2})}{8x^{11}}=\frac{(2x^3)(x^8)}{8x^{11}}=\frac{2x^{3+8}}{8x^{11}}=\frac{2x^{11}}{8x^{11}}=\frac{1}{4}x^{11-11}=\frac{1}{4}x^0=\frac{1}{4}

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