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TEA [102]
3 years ago
7

The value of y varies directly with x2, and y = 150 when x = 5. What is the value of y when x=3?

Mathematics
1 answer:
kow [346]3 years ago
3 0
<span>The value of y when x=3 when the value of y varies directly with x^2, and y = 150 when x = 5 is 54. Since the value of y varies directly with x2, then: y = k * x^2, where k is constant. When y = 150 and x = 5, the value of constant is: 150 = k * 5^2. 150 = k * 25. k = 150/25. k = 6. Thus, when x = 3, the value of y will be: y = 6 * 3^2. y = 6 * 9. y = 54.</span>
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Answer:

The ordered pair generated from the equation is (1, 6).

Step-by-step explanation:

An ordered pair is a pair of numbers, representing two variables, in a specific order. For instance, (<em>x</em>, <em>y</em>) = (1, 2) here <em>x</em> = 1 and <em>y</em> = 2.

The equation provided is:

y=2x+4

Check for all the options:

  • A (1, 6): y=2x+4\Rightarrow\ 6=(2\times 1) +4\Rightarrow\ 6=6
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  • C (3, 6): y=2x+4\Rightarrow\ 6=(2\times 3) +4\Rightarrow\ 6\neq10
  • D (8, 16): y=2x+4\Rightarrow\ 16=(2\times 8) +4\Rightarrow\ 16\neq20

Thus, the ordered pair generated from the equation is (1, 6).

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Step-by-step explanation:

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If my answer helped, kindly mark me as the brainliest!!

Thanks!!

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3 years ago
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