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Bond [772]
3 years ago
12

Jessica conducts an experiment. She flips a coin 100 times. In her experiment she gets heads 40 times and tails 60 times. Based

on her results, if she flipped the coin another 50 times, she should expect to flip heads _____ times.
Mathematics
2 answers:
Llana [10]3 years ago
8 0

Answer:

i think it would be 90 am sorry if i am wrong.

Step-by-step explanation:

egoroff_w [7]3 years ago
3 0

Answer:

20

Step-by-step explanation:

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Someone please help me with this ? Explain and give steps
Drupady [299]
Its an isosceles triangle

angle B = 47

and triangleADB is congruent to triangle ADC

from here we can say that BD = DC

now AD is a median and also altitude

so from here we can say angle x = 90

now in triangle ADB

90+47+y=180(ANGLE SUM PROPERTY )

y= 43
5 0
4 years ago
The opponents of soccer team A are of two types: either they are a class 1 or a class 2 team. The number of goals team A scores
NikAS [45]

Answer:

a) The expected number of goals team A will score is 5.1

b) The probability that team A will score a total of 5 goals is 0.1147

Step-by-step explanation:

Let X be the amount of goals scored by team A in both matches. Let X1 and X2 be the total amount of goals team A scores in match 1 and 2 respectively, then X = X1+X2, and also

a)

E(X) = E(X1+X2) = E(X1)+E(X2) = 0.6*2+0.4*3 + 0.3*2+0.7*3 = 5.1

b) In order for X to be equal to 5 we have 5 possibilities

- X1 is 0 and X2 is 5

- X1 is 1 and X2 is 4

- X1 is 2 and X2 is 3

- X1 is 3 and X2 is 2

- X1 is 4 and X2 is 1

- X1 is 5 and X2 is 0

Let T1 be a poisson distribution with mean λ = 2, then

P(T1=0) = e^{-2}

P(T1=1) = 2 * e^{-2}

P(T1=2) = 2 * e^{-2}

P(T1=3) = \frac{4}{3} \, e^{-2}

P(T1=4) = \frac{2}{3}\, e^{-2}

P(T1=5) = \frac{4}{15}\,e^{-2}

Lets do the same with a Poisson distribution T2 with mean λ = 3

P(T2=0) = e^{-3}

P(T2=1) = 3 \, e^{-3}\\P(T2=2) = \frac{9}{2} \, e^{-3}\\P(T2=3) = \frac{9}{2} \, e^{-3}\\P(T2=4) = \frac{27}{8} \, e^{-3}\\P(T2=5) = \frac{81}{40} \, e^{-3}

Now, we are ready to compute the probability that X is equal to 5.

P(X1 = 0, X2 = 5) = (0.6* e^{-2} + 0.4*e^{-3}) * (0.3*\frac{4}{15}e^{-2}  + 0.7*\frac{81}{40} e^{-3}) = 0.00823\\P(X1 = 1, X2 = 4) = (0.6* 2e^{-2} + 0.4*3 e^{-3}) * (0.3*\frac{2}{3}e^{-2}  + 0.7*\frac{27}{8} e^{-3}) = 0.03214\\P(X1 = 2, X2 = 3) = (0.6* 2e^{-2} + 0.4*\frac{9}{2}e^{-3}) * (0.3*\frac{4}{3}e^{-2}  + 0.7*\frac{9}{2} e^{-3}) = 0.05317\\P(X1 = 3, X2 = 2) = (0.6* \frac{4}{3}e^{-2} + 0.4*\frac{9}{2}*e^{-3}) * (0.3*2e^{-2}  + 0.7*\frac{9}{2} e^{-3}) = 0.0471

P(X1 = 4, X2 = 1) = (0.6* \frac{2}{3}e^{-2} + 0.4*\frac{27}{8}e^{-3}) * (0.3*2e^{-2}  + 0.7*3e^{-3}) = 0.0225\\P(X1 = 5, X2 = 0) = (0.6* \frac{4}{15}e^{-2} + 0.4*\frac{81}{40}e^{-3}) * (0.3*e^{-2}  + 0.7*e^{-3}) = 0.0047

We can conclude that

P(X = 5) = 0.00823+0.03214+0.05317+0.0471+0.0225+0.0047 = 0.1147

The probability that team A will score a total of 5 goals is 0.1147

7 0
3 years ago
.
Art [367]

Answer:

.

<_>

.

()_()

.

Step-by-step explanation:

5 0
3 years ago
The nearest Black hole is 7800 light years from Earth. Light travels at 186,000 per sec how many miles away is it?
Basile [38]
Distance=speed*time
speed of light in miles=3.6 km/hr
7800 light years=7800(9.4607×10^12) km
thus the distance in miles will be as follows:
1 mile=1.60934
thus the distance from each to black hole is:
[7800(9.4607×10^12)]/1.60934
=4.5853244×10^16 miles
5 0
3 years ago
Here is the sample space for three tosses of a coin. {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} calculate te probability that all
maw [93]
Since there are 8 possibilities, but only one of them results in 3 tails tosses, the answer would be 1/8. 1 chance out of 8 possibilities.
8 0
3 years ago
Read 2 more answers
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