Use the distributive property to simplify. (z-6)2

A farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. No fencing is needed along the bar

Luba_88 [7]

The dimensions for the plot that would enclose the most area are a length and a width of 125 feet.

In this question we shall use the first and second derivative tests to determine the optimal dimensions of a rectangular plot of land. The perimeter ( $p$ ), in feet, and the area of the rectangular plot ( $A$ ), in square feet, of land are described below:

$p = 2\cdot (w+l)$ (1)

$A = w\cdot l$ (2)

Where:

$w$ - Width, in feet.
$l$ - Length, in feet.

In addition, the cost of fencing of the rectangular plot ( $C$ ), in monetary units, is:

$C = c\cdot p$ (3)

Where $c$ is the fencing unit cost, in monetary units per foot.

Now we apply (2) and (3) in (1):

$p = 2\cdot \left(\frac{A}{l}+l \right)$

$\frac{C}{c} = 2\cdot (\frac{A}{l}+l )$

$\frac{C\cdot l}{c} = 2\cdot (A+l^{2})$

$\frac{C\cdot l}{c}-2\cdot l^{2} = 2\cdot A$

$\frac{C\cdot l}{2\cdot c} - l^{2} = A$ (4)

We notice that fencing costs are directly proportional to the area to be fenced. Let suppose that cost is the maximum allowable and we proceed to perform the first and second derivative tests:

FDT

$\frac{C}{2\cdot c}-2\cdot l = 0$

$l = \frac{C}{4\cdot c}$

SDT

$A'' = -2$

Which means that length leads to a maximum area.

If we know that $c = 8$ and $C = 4000$ , then the dimensions of the rectangular plot of land are, respectively:

$l = \frac{4000}{4\cdot (8)}$

$l = 125\,ft$

$A = \frac{(4000)\cdot (125)}{2\cdot (8)} -125^{2}$

$A = 15625\,ft^{2}$

$w = \frac{15625\,ft^{2}}{125\,ft}$

$w = 125\,ft$

The dimensions for the plot that would enclose the most area are a length and a width of 125 feet.

We kindly invite to check this question on areas: brainly.com/question/11952845

8 0

3 years ago

What is the most precise name for quadrilateral ABCD with vertices A(–5,2), B(–3, 5),C(4, 5),and D(2, 2)?

bonufazy [111]

Answer: ABCD is a parallelogram.

Step-by-step explanation:

First we plot these point on a graph as given in attachment.

From the attachment we can observe that AD || BC || x-axis .

also, AB ||CD, that will make ABCD a parallelogram , but to confirm we check the property of parallelogram "diagonals bisect each other" , i.e . "Mid point of both diagonals are equal".

Mid point of AC= $(\dfrac{-5+4}{2},\dfrac{2+5}{2})=(\dfrac{-1}{2},\dfrac{7}{2})$

Mid point of BD= $(\dfrac{-3+2}{2},\dfrac{5+2}{2})=(\dfrac{-1}{2},\dfrac{7}{2})$

Thus, Mid point of AC=Mid point of BD

i.e. diagonals bisect each other.

That means ABCD is a parallelogram.

8 0

3 years ago

For a biology project, you measure the weight in grams and the tail length in millimeters of a group of mice. The correlation is

olga nikolaevna [1]

Answer:

Step-by-step explanation:

Given that for a biology project, you measure the weight in grams and the tail length in millimeters of a group of mice.

The correlation is r = 0.9

If you had measured tail length in centimeters instead of millimeters, what would be the correlation?

For this we must understand the meaning of correlation and formula

Correlation is a measure of linear association between the two variables and always lie between -1 and 1

This is got by dividing covariance of (x,y) by product of std deviation of x and y

So because we changed the units of length correlation coefficient would not change.

It would remain the same as 0.90

8 0

3 years ago

Daniel spent 3 hours babysitting for his brother. He and the children played games for 1 3/4 hours and watched television for 1/

____ [38]

Answer:

He spent 3/4 of an hour reading stories

Step-by-step explanation:

Sorry I dont have time :(

8 0

3 years ago

A trade magazine routinely checks the drive-through service times of fast-food restaurants. Upper AA 9595% confidence interva

Butoxors [25]

Answer:

One can be 95% confident that the drive-through service times of fast-food chain is between 169 seconds and 172 seconds.

Step-by-step explanation:

The confidence interval gives a range of value for the population mean or parameter, which is calculated from the statistic value of the data (that is sample statistic). This range gives the interval which is associated with a certain level of confidence for which the interval will contain the true value of the unknown parameter (true value). In the scenario above, the associated confidence level is 95%.Hence, we can be 95% confident that the true value will be continued with the interval (169 ; 172)

6 0

3 years ago