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Scilla [17]
3 years ago
15

In cattle, codominance of the allele for a red coat (R) and the allele for a white coat (W) results in offspring with a roan coa

t (RW); that is, a coat with both red and white hairs.
Cross a roan cow and a roan bull. What are the genotype and phenotype ratios of their offspring?

Biology
1 answer:
mario62 [17]3 years ago
7 0

Answer:

Genotype ratio: 1 (RR) : 2 (RW) : 1 (WW)

Phenotype ratio: 1 Red : 2 Roan : 1 White

Explanation:

Codominance is a kind of inheritance pattern in which both alleles are equally dominant in a gene. This means that both alleles when in a heterozygous state will be simultaneously expressed. According to this question, allele for a red coat (R) and the allele for a white coat (W) results in offspring with a roan coat (RW) in cattle.

Hence, in a cross between a a roan cow (RW) and a roan bull (RW), the following gametes will be produced: R and W.

Using these gametes in a punnet square (see attached image), the offsprings with the following genotypes will be produced: RR, RW, RW, WW.

Therefore, based on the results of the cross;

Genotype ratio: 1 (RR) : 2 (RW) : 1 (WW)

Phenotype ratio: 1 Red : 2 Roan : 1 White

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Complete question:

17. In the 1950’s a young woman sued film star/director Charlie Chaplin for parental support of  her illegitimate child. Charlie Chaplin’s blood type was already on record as type  AB. The mother of the child had type A (AO) and her son had type O blood (OO).

a. Complete a Punnett square for the possible  cross of Charlie and the mother.

b. The judge ruled in favor of the mother and ordered Charlie Chaplin to pay child  support costs of the child. Was the judge correct in his decision based on blood typing  evidence? Explain why or why not. *refer to any Punnett squares to support your answer.

Answer:

The judge committed a mistake in his decision. There are <u>no chances</u> for this couple to have a child who has 0 blood type.

Explanation:

<u>Available data:</u>

  • Charlie Chaplin’s blood type was AB
  • The mother of the child had type A (AO)
  • The son had type O blood (OO).

Cross: Charlie Chaplin x The Woman

Parental)    IAIB    x    IAi

Gametes) IA   IB       IA     i

Punnett square)    IA          IB

                      IA   IAIA      IAIB

                        i    IAi        IBi

F1)  1/4 = 25% of the progeny would have IAIA genotype, blood type A

      1/4 = 25% of the progeny would have IAi genotype, blood type A

      1/4 = 25% of the progeny would have IAIB genotype, blood type AB

      1/4 = 25% of the progeny wouldl have IBi genotype, blood type B

According to the results of the cross observed in the Punnett square, there are no chances for this couple to have a child who has 0 blood type.

Blood type 0 can only be produced by two recessive alleles i, one inherited from each parent. The mother could provide the recessive allele because she is IBi, but Chaplin could not pass to his progeny any recessive allele.

The judge committed a mistake in his decision.

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