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Brums [2.3K]
4 years ago
11

A pair of shoes at one store normally costs 65.75, but is 20% off. Another store has the same shoes but is offering 25% off. Wha

t is the maximum price the shoes can normally be at the second store so that after the discount they are less expensive than at the first store?
Mathematics
1 answer:
Tamiku [17]4 years ago
6 0

Answer:

The shoes at the other store could be at the most 70.13.

Step-by-step explanation:

In order to find this, we need to set them equal to each other. Start by multiplying the first cost by the amount of the total price you'll be paying.

65.75 * 80%

And the other side would be the amount of the total price being paid times x.

x * 75%

Now set them equal to each other and solve.

65.75 * 80% = x * 75%

52.60 = x * 75%

70.13 = x

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Akimi4 [234]

Answer:

this is not a complete question

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3 years ago
Solve for b. a+3b=5c-9
notka56 [123]

Answer:

(5c-9-a)/3

Step-by-step explanation:

1. subtract a from both sides to isolate the variable and its coefficient

5c-9-a = 3b

2. divide both sides by 3 to isolate b because 3b/3 = b

(5c-9-a)/3 = b

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2 years ago
The length of a rectangular mural is 2 ft more than three times the height. The area is 165 ft^2. Find the height of the mural.
NISA [10]

Answer:

x=-1±4√31/3 ft is the height

Step-by-step explanation:

let the height be x ft.

then the length would be 3x+2

area = L*H= x(3x+2)

165=3x²+2x

0= 3x²+2x -165

dividing the whole equation by 3

0=x²+2x/3-55

(x)²+2(x)(1/3) +(1/3)² -55 -(1/9)=0

(x+1/3)²- 495-1/9=0

(x+1/3)²= 496/9

taking square root on both sides

(x+1/3)= ±4√31/3

x= ±4√31/3-1/3

x=-1±4√31/3 ft is the height

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4 years ago
Simplify 5 √16 + 12 √54 - 3 √8
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20+36. l6-6/2

v. v

decimal form

99.69634936

8 0
3 years ago
PLEASE HELP ASAP WILL GIVE BRAINLIEST 5 STAR RATING THANKS AND BRAINLIEST!
PolarNik [594]

Answer:

<h2>Q1. y = 3</h2><h2>Q2. m∠B = 125°</h2><h2>Q3. m∠SPQ = 110°</h2><h2>Q4. x = 55</h2><h2>Q5. x = 123</h2>

Step-by-step explanation:

<h3>Q1.</h3>

If ABCD is a rectangle, then diagonals are congruent: AC = BD.

We have

AC = 5y - 2

BD = 4y + 1

Substitute:

5y - 2 = 4y + 1           <em>add 2 to both sides</em>

5y - 2 + 2 = 4y + 1 + 2

5y = 4y + 3            <em>subtract 4y from both sides</em>

5y - 4y = 4y - 4y + 3

y = 3

<h3>Q2.</h3>

In a parallelogram opposite angles are congruent. Therefore m∠D = m∠B.

We have m∠D = 125° → m∠B = 125°

<h3>Q3.</h3>

In the rhombus, the diagonals are bisectors of the rhombus angles.

Therefore ∠SPR and ∠QPR are congruent.

We have

m∠SPR = (2x +15)°

m∠QPR = (3x - 5)°

The equation:

2x + 15 = 3x - 5           <em>subtract 15 from both sides</em>

2x + 15 - 15 = 3x - 5 - 15

2x = 3x - 20         <em>subtract 3x from both sides</em>

2x - 3x = 3x - 3x - 20

-x = -20           <em>change the signs</em>

x = 20

Substitute it to the expression m∠SPR = (2x + 15)°:

m∠SPR = (2(20) + 15)° = (40 + 15)° = 55°

m∠SPR = m∠QPR → m∠QPR = 55°

∠SPQ = ∠SPR + ∠QPR → m∠SPQ = 2(55°) = 110°

<h3>Q4.</h3>

In the parallelogram, the sum of the angle measures on one side is 180°.

Therefore we have the equation:

(2x + 15) + x = 180      <em>combine like terms</em>

(2x + x) + 15 = 180           <em>subtract 15 from both sides</em>

3x + 15 - 15 = 180 - 15

3x = 165            <em>divide both sides by 3</em>

3x/3 = 165/3

x = 55

<h3>Q5.</h3>

In a parallelogram opposite angles are congruent.

Therefore z = y and x = 2z + 9 → x = 2y + 9    (*)

In the parallelogram, the sum of the angle measures on one side is 180°.

Therefore x + y = 180     (**)

Substitute (*) to (**)

(2y + 9) + y = 180          <em>combine like terms</em>

(2y + y) + 9 = 180             <em>subtract 9 from both sides</em>

3y + 9 - 9 = 180 - 9

3y = 171          <em>divide both sides by 3</em>

y = 57

Put it to (*):

x = 2(57) + 9

x = 114 + 9

x = 123

5 0
3 years ago
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