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sertanlavr [38]
3 years ago
14

find the area and the circumference of a circle with radius 5yd. use the value 3.14 for like, and don’t round your answer to the

nearest hundredth.
Mathematics
2 answers:
Zanzabum3 years ago
4 0

Answer:

1. Area = 78.5 (using 3.14 as pi)

2. Circumference = 31.4 (using 3.14 as pi)

Step-by-step explanation:

saveliy_v [14]3 years ago
3 0

Step-by-step explanation:

Area=r^2\pi \\Circumference = 2r\pi

The radius is equal to 5 yd. We can use this information to find the are and the circumference. Let's find the area first!

A=(5)^2\pi\\A=25\pi \\A= 78.5

So, the area of the circle is 78.5 yd²

Now, let's find the circumference!

C=2(5)\pi \\C=10\pi \\C= 31.4

So, the circumference of the circle is 31.4 yd

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Answer:

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Step-by-step explanation:

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vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

H_0: p \leq 0.05

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

H_a: p > 0.05

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that \mu = 0.05, \sigma = \sqrt{0.05*0.95}

A random sample of 300 items taken from the production line contained 27 defective items.

This means that n = 300, X = \frac{27}{300} = 0.09

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}

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Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

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1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

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