Q = d - 12
q = 28 - d
d - 12 = 28 - d
d + d = 28 + 12
2d = 40
d = 40/2
d = 20 <== 20 dimes
q = d - 12
q = 20 - 12
q = 8 <== 8 quarters
Answer:
=225/16cm^2
Step-by-step explanation:
Given
The ratio of the length to the width of the rectangle =3:2.
The perimeter of a rectangle = 60cm.
Solution
Let length=3x
width=2x
Perimeter of rectangle=2(length + width)
2(3x+2x)=60
5x*2=60
10X=60
X=60/10
X=6
SO LENGTH =3×6=18cm
WIDTH=2×6
=12cm
Let perimeter of the square=5x
Length of rectangle=6x
6x = 18
X=18/6
X=3
SO PERIMETER OF SQUARE=5×3
4SIDE=15
Side=15/4
Area of square=15/4×15/4
=225/16cm^2
Answer:
x = 0.8 y = 0.6
Step-by-step explanation:
Solve one of the equations for a single variable, I chose the 2nd equation and solved for the variable y and I got y = 2x -1.
Next plug in the value for y into the 1st equation, I got :
2x + 4 ( 2x - 1) = 4
Next solve for x by first distributing the 4 to the (2x-1), this becomes (8x -4) then add like terms and move the -4 to the other side of the equation by addition. I got 10x =8 then I divided 8/10 to solve for x and I got 0.8.
Now plug the value 0.8 in for x in the 2nd equation : 2*(0.8) - y = 1
Then solve for y by subtracting 2*(0.8) or 1.6 from 1 and I got -0.6, lastly divide by -1 to solve for y.
Answer:
1.) divisor multiplied by the proper power of ten = 131
2.) dividend multiplied by the proper power of ten = 47
3.) quotient = 2.787
Step-by-step explanation:
1. To make the divisor a whole number you should multiply it by = 100
And the divisor and the dividend must be multiplied by the same power of ten, that is = 100.
So, multiplyind the divisor by = 100:
And multiplyind the dividend by = 100:
2. Obtain the quotient:
Using the calculator you obtain the quotient between divisor and dividend:
Equation 1: 3x + 2y + 4z = 12
Equation 2: x + y + 2z = 6
Substituting x = 0, y = 4 and z = 1 into equation 1 and equation 2 and if the answer equals to 12 and 6 then the two lines intersect at the given point
Equation 1 ⇒ 3(0) + 2(4) + 4(1) = 0 + 8 + 4 =12
Equation 2 ⇒ 0 + 4 + 2(1) = 4 + 2 = 6
We have the answer of 12 and 6, hence the two lines intersect at the given point
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Equation 1: -2x - 4y + z = 8
Equation 2: 4x + 2y = -5
Given point: x = -2, y = 0, and z = 3
Equation 1 ⇒ -2(-2) - 4(0) + 3 = 4 - 0 +3 = 7
Equation 2 ⇒ 4(-2) + 2(0) = -8 + 0 = -8
The answers are not 8 and -5 hence the lines don't intersect at given point