A taxi charges a base fee plus $0.75/km.
2 answers:
Answer:
a) $0.75/Km
b)
c) The fixed base charge
Step-by-step explanation:
We know the taxi charges $0.75 per km and we are told a 10-Km trip costs $8.70. We can clearly see there is a base charge and a variable charge
a) The rate of change tells us the variation of the charges with the distance of the trip. In this case, the rate of change is $0.75/Km
b) If x is the length of the trip in Km, the equation of the total fare F(x) is
We know a 10-Km trip costs $8.70. Replacing those values would give us the value of A
8.70=A+0.75(10)
8.70=A+7.5
Using the value of A we have
c) The initial value represents the charge a customer has to pay even if they don't travel any distance, i.e. the fixed base charge
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Answer:
a)
b)
c) A. A student given a $1 bill is more likely to have kept the money.
Because the probability 0.659 is atmoslt two times greater than 0.341
Step-by-step explanation:
Assuming the following table:
Purchased Gum Kept the Money Total
Students Given 4 Quarters 25 14 39
Students Given $1 Bill 15 29 44
Total 40 43 83
a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.
For this case let's define the following events
B= "student was given $1 Bill"
A="The student spent the money"
For this case we want this conditional probability:
We have that
And if we replace we got:
b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.
For this case let's define the following events
B= "student was given $1 Bill"
A="The student kept the money"
For this case we want this conditional probability:
We have that
And if we replace we got:
c. what do the preceding results suggest?
For this case the best solution is:
A. A student given a $1 bill is more likely to have kept the money.
Because the probability 0.659 is atmoslt two times greater than 0.341