2 years ago

Need the answer to part a and part b please :)

Mathematics

1 answer:

iris [78.8K]2 years ago

8 0

Answer:

55° and 76°

Step-by-step explanation:

An inscribed angle is half the measure of its intercepted arc.

(a)

∠ IDE = $\frac{1}{2}$ × IE = 0.5 × 110° = 55°

(b)

arc TD = 2 × ∠ TED = 2 × 38° = 76°

You might be interested in

What is the domain and derivative of f(x)=ln(2xsqrt(2+x))?

harkovskaia [24]

Domain is the numbers yo can use
we has a sqrt and a ln
we cant have any neagtive ln's or sqrts
x cannot be negative
it cannot be 0 either
domain is all numbers bigger than 0

deritivive
apply chain rule
dy/dx(f(g(x))=f'(g(x))g'(x)
and also
dy/dx (lnx)=1/x
and
dy/dx(f(x)g(x))=f'(x)g(x)+g'(x)f(x)
and from experience
dy/dx(sqrtx)=1/(2√x)

so

dy/dx(ln(2xsqrt(2+x)))=
(1/(2xsqrt(2+x))(2)(sqrt(2+x)+(x/(2sqrt(2+x))=
(3x+4)/(2x(x+2))

domain is all real numbers greater than 0
derivitive is $\frac{3x+4}{2x(x+2)}$