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3 years ago

Need the answer to part a and part b please :)

Mathematics

1 answer:

iris [78.8K]3 years ago

8 0

Answer:

55° and 76°

Step-by-step explanation:

An inscribed angle is half the measure of its intercepted arc.

(a)

∠ IDE = $\frac{1}{2}$ × IE = 0.5 × 110° = 55°

(b)

arc TD = 2 × ∠ TED = 2 × 38° = 76°

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What is the sum of the fractions? Use the nurnber line and equivalert fractions to help find the answer.

alukav5142 [94]

Answer:

-3/4

Step-by-step explanation:

-5/4 + 2/4 = -3/4

Hope this helps :)

7 0

3 years ago

Helppppppp show the steps to your answer

Studentka2010 [4]

The numeric value of the expression -a² - 2bc - |c| for a = -3, b = -5 and c = 2 is of 9.

<h3>How to find the numeric value of an expression?</h3>

The numeric value of an expression is found replacing each letter by it's attributed value.

In this problem, the expression is:

-a² - 2bc - |c|

The attributed values are:

a = -3, b = -5 and c = 2

Hence the numeric value will be given by:

-a² - 2bc - |c| = -(-3)² - 2(-5)(2) - |2| = -(9) + 20 - 2 = -9 + 18 = 9.

More can be learned about the numeric value of an expression at brainly.com/question/14556096

#SPJ1

4 0

1 year ago

SOMEONE PLEASE HELP ME! I have a few of the explanations but I'm not sure if I need more please suggest some thank you

lesantik [10]

Answer:

For tingle #1

We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.

$C=180-(A+B)$

$C=180-(21.24+27.14)$

$C=131.62$

We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.

For triangle #2

In this one, we can find everything and there is one one value for each.

- We can find side c

Since we have a right triangle, we can find side c using the Pythagorean theorem

$b^2=a^2+c^2$

$4^2=2^2+c^2$

$16=4+c^2$

$12=c^2$

$c=\sqrt{12}$

$c=2\sqrt{3}$

- We can find angle C using the cosine trig identity

$cos(C)=\frac{adjacent}{hypotenuse}$

$cos(C)=\frac{2}{4}$

$C=arccos(\frac{2}{4} )$

$C=60$

- Now we can find angle A using the triangle sum theorem

$A=180-(B+C)$

$A=180-(90+60)$

$A=30$

For triangle #3

Again, we can find everything and there is one one value for each.

- We can find angle A using the triangle sum theorem

$A=180-(B+C)$

$A=180-(90+34.88)$

$A=55.12$

- We can find side a using the tangent trig identity

$tan(C)=\frac{opposite-side}{adjacent-side}$

$tan(34.88)=\frac{7}{a}$

$a=\frac{7}{tan(34.88)}$

$a=10.04$

- Now we can find side b using the Pythagorean theorem

$b^2=a^2+c^2$

$b^2=10.04^2+7^2$

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$b=\sqrt{149.8}$

5 0

3 years ago

If 3a-2b= 8 and a+3b=7 what is the value of 4a+b?

Fittoniya [83]

Step 1: Find the value of one variable in terms of the other.

$a+3b=7\\a=7-3b$

Step 2: Substitute the value you just found for this variable in the other equation.

$3a-2b=8\\3(7-3b)-2b=8\\21-9b-2b=8\\21-11b=8\\21=8+11b\\13=11b\\\frac{13}{11}=b\\ b=1\frac{2}{11}$

Step 3: Use your new value for the second variable to find the first.

$a+3b=7\\a+3(1\frac{2}{11})=7\\a+3\frac{6}{11}=7\\\\a=3\frac{5}{11}$

Now that we know the values for a and b we can find the value of 4a+b.

$4a+b\\4(3\frac{5}{11})+1\frac{2}{11}\\12+\frac{20}{11}+1\frac{2}{11}\\\\12+1\frac{9}{11}+1\frac{2}{11}\\\\\boxed{15}$

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3 years ago

PLEASE MAKE SURE HELP ME!

bulgar [2K]

Answer:

1. The first problem is wrong, it should be 0.5(3(15) + 2(20)) because the parentheses make sure that every purchased item is being divided by 2 (multiplying by 0.5 is the same as dividing by 2)

2. The second problem is partially correct. The first two answers you have checked are correct, but the last one is wrong. The third answer should be 6 + 12 instead because that's just a simplified version of 2(3) + 6(2), meaning they are equal

3. I cannot read your answers in the "Why or Why Not" column in the third problem, but the answers you gave in the "Evaluate" and "Does It Work?" columns are all correct.

7 0

3 years ago