(2 The cost of a classified ad is determined by

If a = band b = c, which statement must be true?

faust18 [17]

Answer:

a is still equal to band a

Step-by-step explanation:

a=band b then band b= band c and so on

8 0

3 years ago

Please help me with this problem !!!

Alborosie

Answer:

all you have to do is select all numbers that are 0 or less

anything above 0 is wrong

Hope it Helps!

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500

Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking, $\frac{d(w)}{dt}$ = 3 ft/sec

Rate at which the man is walking, $\frac{d(m)}{dt}$ = 2 ft/sec

Collective rate of both, $\frac{d(m+w)}{dt}$ = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min = 20 min

Now,

Distance traveled by man and woman are $m$ and $w$ ft respectively.

⇒ $m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft$

⇒ $w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\ ft$

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate $\frac{dh}{dt}$ .

Lets calculate h.

Applying Pythagoras formula.

⇒ $h^2=(m+w)^2+500^2$

⇒ $h=\sqrt{(2400+2700)^2+500^2} = 5124.45$

Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ $h^2=(m+w)^2+500^2$

⇒ $2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt} + \frac{d(500)}{dt}$

⇒ $\frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}$ ...as $\frac{d(500)}{dt}= 0$

⇒ Plugging the values.

⇒ $\frac{d(h)}{dt} =\frac{2(2400+2700)(5)}{2\times 5124.45}$ ...as $\frac{d(m+w)}{dt} = 5$ ft/sec

⇒ $\frac{d(h)}{dt} =4.9761$ ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

3 0

4 years ago

A varies directly with B. If A=44 when B=110, find A when B=140

Kay [80]

$\frac{44}{a} = \frac{110}{140}$

$a = \frac{44 \times 140}{110} = 56$

7 0

4 years ago

Hey can anyone pls help me in dis real quick!!!!!

ser-zykov [4K]

Answer:

1) you use any parallel lines or rectangles we can double the triangle to get the area and then divide by 2 as we know the length is 92.5yards and we know the width is 53.5 yards.

We would x these by each other and then divide by 2.

We have the width 53 1/2 yards wide and convert this to decimal if we want.

= 53.5 yards.

We then can count the yards for the length = 90 hash marks = 90 yards+ 2.5

= 92.5yards.

We square then add to find the hypotenuse diagonal line but it is an estimate as the lines inscribed subtends into the corner and it becomes a little larger as bottom line is used. Diagonal is found after by doing a reverse equation on the area.

53.5 x 92.5 then divide by 2 = 4948.75/2 = 2474.375

then 2474.375/ 26.75 = 92.5

This proves the line is isosceles and also find the height of the triangle.

But only as an estimate as the actual line distends

Last answer is B and W are equal measures this is because we do not see a right angle and if we bisected the triangle from the goal line to the left side we would prove the midpoint goal line is actually equal and makes lines of play isosceles where two sides are the same at point B and W.

So the answer is 1 yard as B runs the length of the goal back to a position of diagonal run.

The diagonal length is 92.5 yards

Step-by-step explanation:

8 0

4 years ago