Answer:
The jar has 32 dimes and 18 quarters
Step-by-step explanation:
<u>To solve this problem we can create a system of linear equations in terms of two-variables (say </u>
<u> and </u>
<u>) and solve it.</u> To begin let us analyze the problem further. We know that the values of each coin type are:
Dimes ( ) = $0.10
Quarters( ) = $0.25
Total Value = $7.70
Total Coins = 50
Now let us set up our system of equations as:
Eqn.(1)
Eqn.(2)
Lets take Eqn.(2) and rerrange it to solve for as:
Eqn.(3)
Now lets plug this, in Eqn.(1) so we get the value of as:
Plugging in 
back in Eqn.(3) we finally have:
Thus we conclude that in the jar the coins are:
Dimes ( ) 
Quarters( ) 
Answer:
im assuming c
Step-by-step explanation:
ut i think im wrong. the false statement goes with a though
The answer is x=2/3!! Hope this helped
Answer:
50 nickels, 20 quarters.
Step-by-step explanation:
System of equations (q = # of quarters, n = # of nickels):
<em>q + n = 70, 0.25q + 0.05n = 7.50</em>
the first equation can be changed to q = 70 - n, so we are able to <em>substitute q with 70 - n</em>.
So, it will look like <em>0.25*70 - 0.25n + 0.05n = 7.50</em>. This can be simplified to <em>0.2n = 10</em>, which means that n = 50.
Knowing that we can solve <em>q + 50 = 70</em>, which means that q = 20.
