A moneybag contains 10 nickles and quarters that total is $1.50. How many of each are there?
2 answers:
Answer:
5 Quarters
5 Nickels
Step-by-step explanation:
Amount of nickels: n
Amount of quarters: q
n = 5 cents
q = 25 cents
n+q=10
5n + 25q =150
n=10-q
Substitute.
5(10-q)+25q=150
50-5q+25q=150
50+20q=150
20q=100
q=5
5 Quarters
5 Nickels
The other question:
Dimes = D
Quarters = Q
d + q = 13
q = 13 - d
10d + 25(13 - d) = 220
Solve this equation.
10d + 325 - 25d = 220
325 - 15d = 220
325 = 220 + 15d
105 = 15d
7 = d
<u>7 dimes </u>
<u>6 quarters</u>
Third question:
11 tickets total = $34
Number of children's tickets = c
Number of adult's tickets = a
c = $2
a = $4
c + a = 11
a = 11 - c
2c + 4(11-c) = 34
2c + 44 - 4c = 34
44 - 2c = 34
44 = 34 + 2c
10 = 2c
5 = c
<u>5 children's tickets</u>
<u>6 adult's tickets</u>
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