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4 years ago

-7/9m = 11/6 what is m

2 answers:

4 0

7/9m = 11/6
7 * 6 = 11 * 9m
42/11 = 9m
Then
9m = 42
m = 42/9
    = 14/3
    = 4 2/3
7/9m = 11/6
7 * 6 = 11 * 9m
42/11 = 9m
Then
9m = 42
m = 42/9
    = 14/3
    = 4 2/3
So the value of m comes out to be 4 2/3. I hope the procedure is clear enough for you to understand. In future you can use this procedure to solve similar problems without requiring any help from outside. Only be careful about the calculation part. The cross multiplication part should be done carefully to avoid any mistakes.

OlgaM077 [116]4 years ago

3 0

-7/9m= 11/6
⇒ m= 11/6/ (-7/9)
⇒ m= 11/6* (-9/7)
⇒ m= -2 5/14

Final answer: m= -2 5/14~

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(f) The probability that she must call 3 or 4 dealerships is 0.2497.

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The random variable X can be defined as the number of dealerships the customer needs to call before she finds a used red Miata car.

(b)

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X = 1, 2, 3, 4,...

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The random variable X is defined as the number of trials before the first success. Each trial is independent of the others. And each trial has a similar probability of success.

This implies that the random variable X follows a Geometric distribution.

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The expected value of a Geometric distribution is:

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(e)

Compute the probability that she must call at most 4 dealerships as follows:

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$=\sum\limits^{4}_{x=1}{(1-0.28)^{x-1}\times 0.28}\\=0.28+0.2016+0.1452+0.1045\\=0.7313$

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(f)

Compute the probability that she must call 3 or 4 dealerships as follows:

P (X = 3 or X = 4) = P (X = 3) + P (X = 4)

$=[(1-0.28)^{2-1}\times 0.28]+[(1-0.28)^{4-1}\times 0.28]\\=0.14515+0.10451\\=0.24966\\\approx0.2497$

Thus, the probability that she must call 3 or 4 dealerships is 0.2497.

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