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Kay [80]
3 years ago
14

Convert 5 square root of a into exponential form?

Mathematics
1 answer:
stich3 [128]3 years ago
6 0

Answer:

The answer is:  " 5a^\frac{1}{2} "  .

_____________________________________________

Step-by-step explanation:

______________________________________________

We are asked to convert "5 square root of a"  ;  into "exponential form".

Note that "5 square root of a" ;

             or;  " 5 root a " ;

means:    " 5 times the {square root of the variable, "a" };

      or :    " 5 multiplied by the {square root of the variable, "a" }.

_______________________________________________

This can be written as:   " 5\sqrt{a} " .

_______________________________________________

<u>Note the following property of exponents</u>:

\sqrt[n]{a^m} = (\sqrt[n]{a})^m = a^m^n .

_____________________________________________

So;  to write:  " √a "  ;  <u> </u><em><u>as an exponent</u></em><u> </u> :

______________________________________________

<u>Note</u>:  

" \sqrt{a}  = \sqrt[2]{a} =   \sqrt[2]{a^1} = (\sqrt[2]{a})^1 =  a^\frac{1}{2} " .

_______________________________________________

<u>So</u>:

" \sqrt{a}  =  a^\frac{1}{2} "  ;

_______________________________________________

<u>And</u>:

________________________________________________

" 5\sqrt{a}  =  5a^\frac{1}{2} " .

________________________________________________

   →   The answer is:  " 5a^\frac{1}{2} " .

________________________________________________

Hope this helps!

   Best wishes in your academic endeavors

           — and within the "Brainly" community!

________________________________________________

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Answer:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Solution to the problem

Let X the random variable that represent the number of gallons of a population, and for this case we know the distribution for X is given by:

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We are interested on this probability

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And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

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And we can find this probability with the following difference:

P(-0.714

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.714

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