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Marysya12 [62]
3 years ago
15

OK I need help the answer is c but I didn't understand the teacher explanation pls help me

Mathematics
1 answer:
serg [7]3 years ago
7 0
9 - 6 + 4 - 8/3 ..,
geometric series a(n) = a1r^(n-1)

r = a(n+1)/a(n)
-6/9 = -2/3
4/-6 = -2/3
-8/3/4 = -2/3
so r = -2/3 and a1 = 9

Sn = a1(1-r^n)/(1-r) = 9(1-(-2/3)^n)/(1-(-2/3))
n is infinite Sn = 9/(5/3) = 27/5
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Can you help me solve this problem
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0.4%

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3 0
3 years ago
Suppose your dean of admissions is considering surveying high school seniors about their perceptions of your school to design be
KonstantinChe [14]

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They are more convenient than face to face interviews

They are alot more cost-effective

There is a wider geographical access as you can reach people in other countries too

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3 years ago
What is b1 and r of geometrical sequence if b3 −b1 = 16 and b5 −b3 = 144.
Naily [24]

Answer:

b1 = 2 ; r = 3

Step-by-step explanation:

Given that :

if b3 −b1 = 16 and b5 −b3 = 144.

For a geometric series :

Ist term = a

Second term = ar

3rd term = ar^2

4th term = ar^3

5th term = ar^4 ;...

If b3 - b1 = 16;

ar^2 - a = 16

a(r^2 - 1) = 16 - - - (1)

b5 - b3 = 144

ar^4 - ar^2 = 144

ar^2(r^2 - 1) = 144 - - - - (2)

Divide (1) by (2)

a(r^2 - 1) / ar^2(r^2 - 1) = 16 /144

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Substitute for a in ar^2 - a = 16

9a - a = 16

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From ar^2 - a = 16

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Hence ;

a = b1 = 2 ; r = 3

7 0
3 years ago
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