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mojhsa [17]
3 years ago
7

Complete the ratio table to convert the units of measure from centimeters to inches or inches to

Mathematics
1 answer:
Crazy boy [7]3 years ago
4 0
Answer

1) 2 inches

2) 25.4cm

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Calculate the volume of the cylinder. Use button, not 3.14. Round answer to the tenth place.
Volgvan

Answer:

68.69 m^3

Step-by-step explanation:

Volume of cone = \frac{1}{3}\pi r^{2}h

= \frac{1}{3}\pi (2.9^{2})(7.8)

= \frac{1}{3}\pi (65.6)\\

= \frac{1}{3}(206)

= 68.69 m^3

7 0
2 years ago
Can I get some help on this I have so many assignments to do and I just want to go to sleep
AfilCa [17]
Hi! It’s me from your other post! Here’s my work for you! It’s been awhile since I’ve done this stuff so I’m really sorry if I get you a bad grade! I just wanted to help out:))

7 0
3 years ago
The number of Roberto’s baseball cards is ¾ the number of David’s cards If Roberto gives ½ of his cards to David, what will be t
inn [45]

Answer:

1/4, 0.25

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
3 years ago
PLEASE HELP :’( last one
valina [46]

Answer:

A.3

Step-by-step explanation:

5 0
3 years ago
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