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Cerrena [4.2K]
3 years ago
15

A jumper costing £90 was sold for £108. find the percentage profit

Mathematics
2 answers:
Anit [1.1K]3 years ago
7 0
In order to solve this you need to do the original price - the sold price and figure the difference.

90-180= <span>£</span>18

therefore making it 20% of a profit sale.
True [87]3 years ago
7 0
16.66 repeating, have a good day
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1. How much does the glass for region 1 cost?
Simora [160]

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1) 0.10

2) 0.15

3) 0.100

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1 year ago
A number line going from negative 3 to positive 5. A closed circle is at negative 1.5. Everything to the left of the circle is s
kykrilka [37]

the inequality in the number-line is:

x ≤ -1.5

<h3></h3><h3>Which inequality is represented?</h3>

We know that we have a closed circle at -1.5, this means that the value is a solution of the inequality.

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x ≤ -1.5

If you want to learn more about inequalities:

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5 0
2 years ago
Hola me ayudan con esta pregunta TRANSFORMAR LOS SIGUIENTES DECIMALES EN FRACCIÓN, 1.- 8,485 2.- 125,65 3.- 54,987987... 4.- 266
Nitella [24]

Answer:

Ve la respuesta abajo

Step-by-step explanation:

Para hacer la conversión de decimales a fracción, es necesario hacer dos cosas:

1. Identificar el tipo de decimal (finitos, infinito periódico, infinito semi periódico).

2. Aplicar la expresión o formula correspondiente, dependiendo del tipo de decimal.

Un decimal finito es aquel que solo tiene un número determinado de decimales y no se extiende al infinito.

Un decimal infinito periódico, es aquel cuya cifra decimal se repite constantemente hasta el infinito, esto puede ser un decimal, dos, etc.

Un decimal semi infinito periódico es aquel donde una parte de los decimales se mantiene sin repetir, y la otra parte se repite hasta el infinito.

Una vez que hayas identificado el tipo de decimal, solo debes aplicar alguna de los 3 casos siguientes:

1. PAra un decimal finito se convierte la cifra decimal en un numero entero multiplicando por 10, 100, 1000 depende del número de decimales que tenga, y se divide entre 10, 100, 1000.... segun el número de decimales y se simplifica la fracción si es posible.

2. Para un infinito periódico se anota el número y se le resta él o los números que están antes del período. Se coloca como denominador un 9 por cada número que está en el período (si hay un número bajo la rayita se coloca un 9, si hay dos números bajo el período se coloca 99, etc.). Si se puede simplificar, se simplifica.

3. El numerador de la fracción se obtiene, restando al número la parte entera y el anteperíodo, o sea, todo lo que está antes de la “rayita”.  El denominador de la fracción se obtiene colocando tantos 9 como cifras tenga el período y tantos 0 como cifras tenga el anteperíodo. Como siempre, el resultado se expresa como fracción irreductible (no se puede simplificar más) o como número mixto.

Dicho esta parte teórica, pasemos a la práctica y convirtamos los decimales a fracción:

1. 8,485: decimal finito, con 3 decimales, lo anotamos sin la coma, y entonces colocas como denominador el 1000, porque fueron 3 decimales, 3 ceros ----------> 8485/1000 = 1697/200   (se simplificó por 5)

2.  125,65: decimal finito -----> 12565/100 = 2513/20

3. 54,987987: infinito periódico, aplicamos los pasos de arriba:

54,987987 = 54987 - 54 / 999 = 54933 / 999

4. 266.8484..: infinito periódico

266,8484.... = 26684 - 266 / 99 = 26418 / 99

5. 4,78999.: Infinito semiperiódico

4,78999 = 4789 - 478 / 900 = 4311 / 900

6. 942,74111: infinito semiperiódico

942,74111 = 942741 - 94274 / 900 = 848467 / 900

Espero te sirva

3 0
3 years ago
Help with this question please?
tatuchka [14]

Answer:

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Step-by-step explanation:

You can think of an ellipse as a circle with a different scale factor in the x-direction than in the y-direction. When either dimension is stretched by a factor of k, the corresponding variable (v) is replaced by (v/k).

Here, the unit circle

  x^2 +y^2 = 1

is stretched by a factor of 3 vertically (in the y-direction) and a factor of 5 horizontally (in the x-direction). That means we can replace x with (x/5) and  y with (y/3) in the above equation to get ...

  (x/5)^2 +(y/3)^2 = 1

Traditionally, the denominator is written as a number, not a square, so the equation would be ...

  x^2/25 +y^2/9 = 1

4 0
3 years ago
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