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3 years ago

POINTS!!! Does anyone do FLVS? If so, can you please help me with 06.02 Factory Workers (History) I really need help :(

Mathematics

1 answer:

viva [34]3 years ago

8 0

Answer:

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Need help will mark brainliest

Tcecarenko [31]

I think it’s going to be 4/16 but I’m not a math major and I suck at math so I’m not sure

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3 years ago

How do you find the domain of a function?

emmasim [6.3K]

Domain of the function is x in order pair for example (2,3) 2 is the domain

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2 years ago

Solve the equation 4(x-5)=2x-14

Ganezh [65]

4x-20=2x-14
-2x. -2x
2x-20=14
+20 +20
2x= 34
— —
2 2
X=17

Therefore x=17

5 0

3 years ago

Read 2 more answers

For the differential equations dydx=sqrt(y^2−36) does the existence/uniqueness theorem guarantee that there is a solution to thi

julsineya [31]

Answer:

1. (-4,6) there is no a solution to the equation through this point

2. (2,−6) there is no a solution to the equation through this point

3. (−5,39) there is a solution to the equation through this point

4. (−1,45) there is a solution to the equation through this point

Step-by-step explanation:

Using the existence and uniqueness theorem:

Let:

$F(x,y)=\sqrt{y^2-36} \\\\and\\\\\frac{\partial F}{\partial y} =\frac{y}{\sqrt{y^2-36} }$

Now, let's find the domain of $F(x,y)$ , due to the square root:

$y^2-36 \geq 0\\\\y^2\geq 36\\\\y \geq 6\hspace{12}or\hspace{12}y\leq-6$

So the domain of the function is:

$y \in R\hspace{12}y\geq6\hspace{12}or\hspace{12}y\leq-6$

Now, due to the fraction $\frac{\partial F}{\partial y}$ the denominator must be also different from 0, so:

$y^2-36\neq0\\\\y \neq \pm6$

So, the theorem tells us that for each $y_0\in R:\hspace{12}y_0>6\hspace{12}or\hspace{12}y_0$ there exists a unique solution defined in an open interval around $x_0$ .

1. (-4,6) there is no a solution to the equation through this point because $y_0=6$

2. (2,−6) there is no a solution to the equation through this point because

$y_0=-6$

3. (−5,39) there is a solution to the equation through this point because

$y_0>6$

4. (−1,45) there is a solution to the equation through this point because

$y_0>6$

6 0

3 years ago

24 out of the 96 teachers in a school staff meeting were first-year teachers. What percentage of the teachers in the meeting wer

Mila [183]

25%. 24/96= .25 = 25%

3 0

3 years ago

Read 2 more answers