3 years ago

URGENT! CINE SE PRICEPE LA MATEMATICĂ. [CLASA A 8-A]

Mathematics

1 answer:

kiruha [24]3 years ago

7 0

The answer is yes but its could be false or 6:00

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Answer:

CD ≠ EF

Step-by-step explanation:

Using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = C(- 2, 5) and (x₂, y₂ ) = D(- 1, 1)

CD = $\sqrt{(-1+2)^2+(1-5)^2}$

= $\sqrt{1^2+(-4)^2}$

= $\sqrt{1+16}$ = $\sqrt{17}$

Repeat using (x₁, y₁ ) = E(- 4, - 3) and (x₂, y₂ ) = F(- 1, - 1)

EF = $\sqrt{(- 1+4)^2+(-1+3)^2}$

= $\sqrt{3^2+2^2}$

= $\sqrt{9+4}$ = $\sqrt{13}$

Since $\sqrt{17}$ ≈ $\sqrt{13}$ , then CD and EF are not congruent

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