Well u need to give me the equation and the substitutions for the variables then I can solve it
1300 = 1000 (1.08)^t
1.3 = (1.08)^t
log base 1.08 (1.3) = t
3.41 = t
Required algebraic expression is 8/(x - m)
400cm = 0.004km.
Perhaps there is something else your question meant, but it is way to unspecific.
