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Ira Lisetskai [31]

2 years ago

7

At the beginning of summer, the water level on a pond is 2 feet below its normal level. After an unusually dry summer, the water

level on the pond dropped another 2 feet. How far above or below the normal water level is the pond at the end of the summer?

1 answer:

Scilla [17]2 years ago

8 0

Answer:

Step-by-step explanation:

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Oksanka [162]

Formula= Base times height divided by 2

6 x 7= 42
42/ 2
answer= 21

3 0

3 years ago

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Solve the following ODE's: c) y* - 9y' + 18y = t^2

Nastasia [14]

Answer:

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = $C_1e^{3t}+C_2e^{6t}$

now calculating P.I.

$P.I. = \frac{t^2}{D^2 - 9D +18}$

$P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

hence the complete solution

y = C.F. + P.I.

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

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2 years ago

The width of a yeast of grain is approximately 4 micrometers, which is 4*10^-6 meter. Give your answers in scientific notation.

SashulF [63]

Step-by-step explanation:

ok so just take 4×10=40

-6^40=20

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3 years ago

(-1).(2-6)^2÷8+8-3.4

Paha777 [63]

(-1)*(2-6)^2÷8+8-3.4

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-1*16÷8+8-3.4

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3 years ago

What is the answer 1/x divided by 1/y =

Klio2033 [76]

$\frac{\frac{1}{x} }{\frac{1}{y} } =\frac{1}{x} /\frac{1}{y} =\frac{1}{x} *\frac{y}{1} =\frac{y}{x}$

That should be your final answer.

Hope this helps!

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2 years ago

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