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3 years ago

How to graph x+y=3 and x-y=1

2 answers:

7 0

Put them in y= mx+b format. .
x+y=3 ---> y= -x+3
x-y=1 ---> y= x-1
The x's are your slope and the numbers are your y-intercept.
Hope it helps!

stich3 [128]3 years ago

6 0

Isolate y in both the equations so
x+y=3 x-y=1
y=-x+3 y=x-1
your y-intercept is 3 y-intercept is -1
and slope is -1/1 slope is 1/1

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sattari [20]

Answer:

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Step-by-step explanation:

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3 years ago

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An Ontario lottery has the following structure, the first person drawn from the names wins $15 000. Each subsequent person drawn

elixir [45]

The first four terms are : 15000, 14850, 14700, 14550
a = 15000 ; d = -150
The explicit formula is : $a_{n} = - 150n \: + 15150$

The first term of the sequence, a = 15,000

Each subsequent winner gets $150 less

Hence, the common difference, d = - $150

The first four terms :

First term, a1 = $15000

Second term, a2 = a - d = $15000 - $150 = $14850

Third term, a3 = a2 - d = $14850 - $150 = $14700

Fourth term, a4 = a3 - d = $14700 - $150 = $14550

a, for the sequence is the first term = $15000

d, for the sequence is the common $150 (difference between successive wins).

Explicit formula for the general term :

$a_{n} \: = nd \: + c$

For n = 1

$15000 = 1( - 150) + c$

$15000 = - 150 + c$

$c = 15150$

Hence, the explicit formula for the nth term is :

$a_{n} \: = - 150n \: + 15150$

Learn more : brainly.com/question/12006170

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2 years ago

Select the best answer for the question

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Answer:

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Step-by-step explanation:

2x + y < 10

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2 years ago

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Therefore, The conversion of unit is $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

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VMariaS [17]

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The second tank is filling faster.

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