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Paladinen [302]
3 years ago
13

How to graph x+y=3 and x-y=1

Mathematics
2 answers:
guapka [62]3 years ago
7 0
Put them in y= mx+b format. . 
x+y=3 ---> y= -x+3 
x-y=1 ---> y= x-1 
The x's are your slope and the numbers are your y-intercept.
Hope it helps!
stich3 [128]3 years ago
6 0
Isolate y in both the equations so
x+y=3                                                     x-y=1
y=-x+3                                                    y=x-1
your y-intercept is 3                                y-intercept is -1
and slope is -1/1                                      slope is 1/1
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sattari [20]

Answer:

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Step-by-step explanation:

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An Ontario lottery has the following structure, the first person drawn from the names wins $15 000. Each subsequent person drawn
elixir [45]
  • The first four terms are : 15000, 14850, 14700, 14550
  • a = 15000 ; d = -150
  • The explicit formula is : a_{n} =  - 150n \:  + 15150

The first term of the sequence, a = 15,000

Each subsequent winner gets $150 less

Hence, the common difference, d = - $150

The first four terms :

First term, a1 = $15000

Second term, a2 = a - d = $15000 - $150 = $14850

Third term, a3 = a2 - d = $14850 - $150 = $14700

Fourth term, a4 = a3 - d = $14700 - $150 = $14550

a, for the sequence is the first term = $15000

d, for the sequence is the common $150 (difference between successive wins).

Explicit formula for the general term :

a_{n} \:  = nd \: + c

For n = 1

15000 = 1( - 150)  + c

15000 =  - 150 + c

c = 15150

Hence, the explicit formula for the nth term is :

a_{n} \:  =  - 150n \:  + 15150

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Select the best answer for the question
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Answer:

C

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Step-by-step explanation:

2x + y < 10

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3x + 2y < 12

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3 0
2 years ago
Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)
Crazy boy [7]

Answer:

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Step-by-step explanation:

To find : Convert 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C} into \frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Solution :

We convert units one by one,

1\text{ m}^2=10.7639\text{ ft}^2

1\text{ sec}=\frac{1}{3600}\text{ hour}

1\text{ cal}=0.003968\text{ BTU}

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Substitute all the values in the unit conversion,

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Therefore, The conversion of unit is 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

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