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nalin [4]
3 years ago
8

AB bisects CD at point B.Find CB if CD=16

Mathematics
1 answer:
Crank3 years ago
8 0

Answer:

cdchDJgxgcvcancel :Halloween costume for Halloween this year and I don't have any questions please feel free to contact

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Solve the System of Equations
soldi70 [24.7K]

Answer:

Equations: x+y=80\,,\,2x+4y=216\,\,

number of chickens = 52

number of goats = 28

Step-by-step explanation:

Given: A small ranch has chickens and goats

Total number of heads = 80

Total number of legs = 216

To find: number of chickens and goats

To draw: the graph

Solution:

Let x denotes number of chickens and y denotes number of goats.

According to the question,

x+y=80\,\,(i)\\2x+4y=216\,\,(ii)

From (i), put x=80-y in (ii)

2(80-y)+4y=216\\160-2y+4y=216\\2y=216-180\\2y=56\\y=\frac{56}{2}=28

Put y=28 in equation (i)

x+28=80\\x=80-28=52

So,

number of chickens = 52

number of goats = 28

Download pptx
6 0
3 years ago
Two planes leave an airport at the same time. Each flies at a speed of 110 mph. One flies in the direction N 60° E. The other fl
Dmitriy789 [7]
40^2 is how far apart the planes are after three hours travel
4 0
2 years ago
Simplify each expression by distributing and combined bf like terms (SHOW WORK) please
Dafna1 [17]

Answer:

c-39

1. rearrange terms

2.distribute

3.distribute

4. subtract the numbers

5. combine like terms

6.multiply by 1

8 0
2 years ago
ANSWER ASAP!!! Find the length of the segment indicated
trapecia [35]

Answer:

14.45

Step-by-step explanation:

x^2+(7.1)^2=(16.1)^2

×^2+50.41=259.21

x^2=208.8

sqrt(x^2)=sqrt(208.8)

x=14.45

check.

14.45^2 + 7.1^2 = 16.1^2

4 0
3 years ago
A lidless box is to be made using 2m^2 of cardboard find the dimensions of the box that requires the least amount of cardboard
Jlenok [28]
1.8, Problem 37: A lidless cardboard box is to be made with a volume of 4 m3 . Find the dimensions of the box that requires the least amount of cardboard. Solution: If the dimensions of our box are x, y, and z, then we’re seeking to minimize A(x, y, z) = xy + 2xz + 2yz subject to the constraint that xyz = 4. Our first step is to make the first function a function of just 2 variables. From xyz = 4, we see z = 4/xy, and if we substitute this into A(x, y, z), we obtain a new function A(x, y) = xy + 8/y + 8/x. Since we’re optimizing something, we want to calculate the critical points, which occur when Ax = Ay = 0 or either Ax or Ay is undefined. If Ax or Ay is undefined, then x = 0 or y = 0, which means xyz = 4 can’t hold. So, we calculate when Ax = 0 = Ay. Ax = y − 8/x2 = 0 and Ay = x − 8/y2 = 0. From these, we obtain x 2y = 8 = xy2 . This forces x = y = 2, which forces z = 1. Calculating second derivatives and applying the second derivative test, we see that (x, y) = (2, 2) is a local minimum for A(x, y). To show it’s an absolute minimum, first notice that A(x, y) is defined for all choices of x and y that are positive (if x and y are arbitrarily large, you can still make z REALLY small so that xyz = 4 still). Therefore, the domain is NOT a closed and bounded region (it’s neither closed nor bounded), so you can’t apply the Extreme Value Theorem. However, you can salvage something: observe what happens to A(x, y) as x → 0, as y → 0, as x → ∞, and y → ∞. In each of these cases, at least one of the variables must go to ∞, meaning that A(x, y) goes to ∞. Thus, moving away from (2, 2) forces A(x, y) to increase, and so (2, 2) is an absolute minimum for A(x, y).
5 0
3 years ago
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