For new line, slope m=2 and y-intercept c=(-10)
Step-by-step explanation:
<em>Note : Figure given is for reference to understand better.</em>
<em>Where redline is for given line and blueline for new line</em>
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The equation of given line 8x-4y=5 and it is dilated by a scale factor of 8 centered at the origin.
Step 1 : Find two points on given line.
When x=0, y=?
When y=0, x=?
We get points
Step 2: Find distance from centered and scale it.
Now, It is said that line 8x-4y=5 dilated by a scale factor of 8 centered at the origin and point A and point B is on same.
So that point A and point B will also get dilated by a scale factor of 8 centered at the origin or distance of points from origin will be scaled by 8.
For point A:
Distance of point from origin is
unit in x-direction and zero
unit in y-direction.
After scaled by factor of 8, the distance will multipy by 8 and new location is
For point B:
Distance of point from origin is
unit in x-direction and zero unit in y-direction.
After scaled by factor of 8, the distance will multipy by 8 and new location is
Step 3: Find Equation of new line.
Points and
make a new line
The equation of given as
Now, Comparing with the equation of the line : y=mx + c
Where m=slope and c is the y-intercept
We get, Slope m=2 and y-intercept c=(-10)
