Question

What is the value of i 97 – i? –i 0 –2i i Superscript 96

Answer 1

The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue

Answer:

$i^{97}-i=0$

Step-by-step explanation:

Powers of The Imaginary Unit

The imaginary unit i is defined as

$i=\sqrt{-1}$

The first powers of i are

$i^0=1$

$i^1=i$

$i^2=(\sqrt{-1})^2=-1$

$i^3=i.i^2=-i$

$i^4=i^2.i^2=1$

And so on the cycle repeats every four numbers. To find the value of $i^{96}$ we can find the remainder of 96/4=0. So $i^{96}=i^0=1$

The given expression is

$i^{97}-i$

Factoring

$i(i^{96}-1)$

Since $i^{96}=1$

$=i(1-1)=0$

The required value is 0

Answer 2

Answer:

The answer is 0

Step-by-step explanation: